635. 设计日志存储系统 🔒

题目描述

你将获得多条日志，每条日志都有唯一的 id 和 timestamp ，timestamp 是形如 Year:Month:Day:Hour:Minute:Second 的字符串，2017:01:01:23:59:59 ，所有值域都是零填充的十进制数。

实现 LogSystem 类：

LogSystem() 初始化 LogSystem 对象
void put(int id, string timestamp) 给定日志的 id 和 timestamp ，将这个日志存入你的存储系统中。
int[] retrieve(string start, string end, string granularity) 返回在给定时间区间 [start, end] （包含两端）内的所有日志的 id 。start 、end 和 timestamp 的格式相同，granularity 表示考虑的时间粒度（例如，精确到 Day、Minute 等）。例如 start = "2017:01:01:23:59:59"、end = "2017:01:02:23:59:59" 且 granularity = "Day" 意味着需要查找从 Jan. 1st 2017 到 Jan. 2nd 2017 范围内的日志，可以忽略日志的 Hour、Minute 和 Second 。

示例：

输入：
["LogSystem", "put", "put", "put", "retrieve", "retrieve"]
[[], [1, "2017:01:01:23:59:59"], [2, "2017:01:01:22:59:59"], [3, "2016:01:01:00:00:00"], ["2016:01:01:01:01:01", "2017:01:01:23:00:00", "Year"], ["2016:01:01:01:01:01", "2017:01:01:23:00:00", "Hour"]]
输出：
[null, null, null, null, [3, 2, 1], [2, 1]]

解释：
LogSystem logSystem = new LogSystem();
logSystem.put(1, "2017:01:01:23:59:59");
logSystem.put(2, "2017:01:01:22:59:59");
logSystem.put(3, "2016:01:01:00:00:00");

// 返回 [3,2,1]，返回从 2016 年到 2017 年所有的日志。
logSystem.retrieve("2016:01:01:01:01:01", "2017:01:01:23:00:00", "Year");

// 返回 [2,1]，返回从 Jan. 1, 2016 01:XX:XX 到 Jan. 1, 2017 23:XX:XX 之间的所有日志
// 不返回日志 3 因为记录时间 Jan. 1, 2016 00:00:00 超过范围的起始时间
logSystem.retrieve("2016:01:01:01:01:01", "2017:01:01:23:00:00", "Hour");

提示：

1 <= id <= 500
2000 <= Year <= 2017
1 <= Month <= 12
1 <= Day <= 31
0 <= Hour <= 23
0 <= Minute, Second <= 59
granularity 是这些值 ["Year", "Month", "Day", "Hour", "Minute", "Second"] 之一
最多调用 500 次 put 和 retrieve

解法

方法一：字符串比较

将日志的 id 和 timestamp 作为元组存入数组中，然后在 retrieve() 方法中，根据 granularity 截取 start 和 end 的相应部分，然后遍历数组，将符合条件的 id 加入结果数组中。

时间复杂度方面，put() 方法的时间复杂度为 $O(1)$，retrieve() 方法的时间复杂度为 $O(n)$，其中 $n$ 为数组的长度。

Python3JavaC++Go

class LogSystem:
    def __init__(self):
        self.logs = []
        self.d = {
            "Year": 4,
            "Month": 7,
            "Day": 10,
            "Hour": 13,
            "Minute": 16,
            "Second": 19,
        }

    def put(self, id: int, timestamp: str) -> None:
        self.logs.append((id, timestamp))

    def retrieve(self, start: str, end: str, granularity: str) -> List[int]:
        i = self.d[granularity]
        return [id for id, ts in self.logs if start[:i] <= ts[:i] <= end[:i]]


# Your LogSystem object will be instantiated and called as such:
# obj = LogSystem()
# obj.put(id,timestamp)
# param_2 = obj.retrieve(start,end,granularity)

class LogSystem {
    private List<Log> logs = new ArrayList<>();
    private Map<String, Integer> d = new HashMap<>();

    public LogSystem() {
        d.put("Year", 4);
        d.put("Month", 7);
        d.put("Day", 10);
        d.put("Hour", 13);
        d.put("Minute", 16);
        d.put("Second", 19);
    }

    public void put(int id, String timestamp) {
        logs.add(new Log(id, timestamp));
    }

    public List<Integer> retrieve(String start, String end, String granularity) {
        List<Integer> ans = new ArrayList<>();
        int i = d.get(granularity);
        String s = start.substring(0, i);
        String e = end.substring(0, i);
        for (var log : logs) {
            String t = log.ts.substring(0, i);
            if (s.compareTo(t) <= 0 && t.compareTo(e) <= 0) {
                ans.add(log.id);
            }
        }
        return ans;
    }
}

class Log {
    int id;
    String ts;

    Log(int id, String ts) {
        this.id = id;
        this.ts = ts;
    }
}

/**
 * Your LogSystem object will be instantiated and called as such:
 * LogSystem obj = new LogSystem();
 * obj.put(id,timestamp);
 * List<Integer> param_2 = obj.retrieve(start,end,granularity);
 */

class LogSystem {
public:
    LogSystem() {
        d["Year"] = 4;
        d["Month"] = 7;
        d["Day"] = 10;
        d["Hour"] = 13;
        d["Minute"] = 16;
        d["Second"] = 19;
    }

    void put(int id, string timestamp) {
        logs.push_back({id, timestamp});
    }

    vector<int> retrieve(string start, string end, string granularity) {
        vector<int> ans;
        int i = d[granularity];
        auto s = start.substr(0, i);
        auto e = end.substr(0, i);
        for (auto& [id, ts] : logs) {
            auto t = ts.substr(0, i);
            if (s <= t && t <= e) {
                ans.emplace_back(id);
            }
        }
        return ans;
    }

private:
    vector<pair<int, string>> logs;
    unordered_map<string, int> d;
};

/**
 * Your LogSystem object will be instantiated and called as such:
 * LogSystem* obj = new LogSystem();
 * obj->put(id,timestamp);
 * vector<int> param_2 = obj->retrieve(start,end,granularity);
 */

type LogSystem struct {
    logs []pair
    d    map[string]int
}

func Constructor() LogSystem {
    d := map[string]int{
        "Year":   4,
        "Month":  7,
        "Day":    10,
        "Hour":   13,
        "Minute": 16,
        "Second": 19,
    }
    return LogSystem{[]pair{}, d}
}

func (this *LogSystem) Put(id int, timestamp string) {
    this.logs = append(this.logs, pair{id, timestamp})
}

func (this *LogSystem) Retrieve(start string, end string, granularity string) (ans []int) {
    i := this.d[granularity]
    s, e := start[:i], end[:i]
    for _, log := range this.logs {
        t := log.ts[:i]
        if s <= t && t <= e {
            ans = append(ans, log.id)
        }
    }
    return
}

type pair struct {
    id int
    ts string
}

/**
 * Your LogSystem object will be instantiated and called as such:
 * obj := Constructor();
 * obj.Put(id,timestamp);
 * param_2 := obj.Retrieve(start,end,granularity);
 */

635. 设计日志存储系统 🔒

题目描述

解法

方法一：字符串比较

评论