528. 按权重随机选择

题目描述

给你一个 下标从 0 开始 的正整数数组 w ，其中 w[i] 代表第 i 个下标的权重。

请你实现一个函数 pickIndex ，它可以 随机地 从范围 [0, w.length - 1] 内（含 0 和 w.length - 1）选出并返回一个下标。选取下标 i 的概率为 w[i] / sum(w) 。

例如，对于 w = [1, 3]，挑选下标 0 的概率为 1 / (1 + 3) = 0.25 （即，25%），而选取下标 1 的概率为 3 / (1 + 3) = 0.75（即，75%）。

示例 1：

输入：
["Solution","pickIndex"]
[[[1]],[]]
输出：
[null,0]
解释：
Solution solution = new Solution([1]);
solution.pickIndex(); // 返回 0，因为数组中只有一个元素，所以唯一的选择是返回下标 0。

示例 2：

输入：
["Solution","pickIndex","pickIndex","pickIndex","pickIndex","pickIndex"]
[[[1,3]],[],[],[],[],[]]
输出：
[null,1,1,1,1,0]
解释：
Solution solution = new Solution([1, 3]);
solution.pickIndex(); // 返回 1，返回下标 1，返回该下标概率为 3/4 。
solution.pickIndex(); // 返回 1
solution.pickIndex(); // 返回 1
solution.pickIndex(); // 返回 1
solution.pickIndex(); // 返回 0，返回下标 0，返回该下标概率为 1/4 。

由于这是一个随机问题，允许多个答案，因此下列输出都可以被认为是正确的:
[null,1,1,1,1,0]
[null,1,1,1,1,1]
[null,1,1,1,0,0]
[null,1,1,1,0,1]
[null,1,0,1,0,0]
......
诸若此类。

提示：

1 <= w.length <= 10⁴
1 <= w[i] <= 10⁵
pickIndex 将被调用不超过 10⁴ 次

解法

方法一

Python3JavaC++GoRustJavaScript

class Solution:
    def __init__(self, w: List[int]):
        self.s = [0]
        for c in w:
            self.s.append(self.s[-1] + c)

    def pickIndex(self) -> int:
        x = random.randint(1, self.s[-1])
        left, right = 1, len(self.s) - 1
        while left < right:
            mid = (left + right) >> 1
            if self.s[mid] >= x:
                right = mid
            else:
                left = mid + 1
        return left - 1


# Your Solution object will be instantiated and called as such:
# obj = Solution(w)
# param_1 = obj.pickIndex()

class Solution {
    private int[] s;
    private Random random = new Random();

    public Solution(int[] w) {
        int n = w.length;
        s = new int[n + 1];
        for (int i = 0; i < n; ++i) {
            s[i + 1] = s[i] + w[i];
        }
    }

    public int pickIndex() {
        int x = 1 + random.nextInt(s[s.length - 1]);
        int left = 1, right = s.length - 1;
        while (left < right) {
            int mid = (left + right) >> 1;
            if (s[mid] >= x) {
                right = mid;
            } else {
                left = mid + 1;
            }
        }
        return left - 1;
    }
}

/**
 * Your Solution object will be instantiated and called as such:
 * Solution obj = new Solution(w);
 * int param_1 = obj.pickIndex();
 */

class Solution {
public:
    vector<int> s;

    Solution(vector<int>& w) {
        int n = w.size();
        s.resize(n + 1);
        for (int i = 0; i < n; ++i) s[i + 1] = s[i] + w[i];
    }

    int pickIndex() {
        int n = s.size();
        int x = 1 + rand() % s[n - 1];
        int left = 1, right = n - 1;
        while (left < right) {
            int mid = left + right >> 1;
            if (s[mid] >= x)
                right = mid;
            else
                left = mid + 1;
        }
        return left - 1;
    }
};

/**
 * Your Solution object will be instantiated and called as such:
 * Solution* obj = new Solution(w);
 * int param_1 = obj->pickIndex();
 */

type Solution struct {
    s []int
}

func Constructor(w []int) Solution {
    n := len(w)
    s := make([]int, n+1)
    for i := 0; i < n; i++ {
        s[i+1] = s[i] + w[i]
    }
    return Solution{s}
}

func (this *Solution) PickIndex() int {
    n := len(this.s)
    x := 1 + rand.Intn(this.s[n-1])
    left, right := 1, n-1
    for left < right {
        mid := (left + right) >> 1
        if this.s[mid] >= x {
            right = mid
        } else {
            left = mid + 1
        }
    }
    return left - 1
}

/**
 * Your Solution object will be instantiated and called as such:
 * obj := Constructor(w);
 * param_1 := obj.PickIndex();
 */

use rand::{ thread_rng, Rng };

struct Solution {
    sum: Vec<i32>,
}

/**
 * `&self` means the method takes an immutable reference.
 * If you need a mutable reference, change it to `&mut self` instead.
 */
impl Solution {
    fn new(w: Vec<i32>) -> Self {
        let n = w.len();
        let mut sum = vec![0; n + 1];
        for i in 1..=n {
            sum[i] = sum[i - 1] + w[i - 1];
        }
        Self { sum }
    }

    fn pick_index(&self) -> i32 {
        let x = thread_rng().gen_range(1, self.sum.last().unwrap() + 1);
        let (mut left, mut right) = (1, self.sum.len() - 1);
        while left < right {
            let mid = (left + right) >> 1;
            if self.sum[mid] < x {
                left = mid + 1;
            } else {
                right = mid;
            }
        }
        (left - 1) as i32
    }
}/**
 * Your Solution object will be instantiated and called as such:
 * let obj = Solution::new(w);
 * let ret_1: i32 = obj.pick_index();
 */

/**
 * @param {number[]} w
 */
var Solution = function (w) {
    const n = w.length;
    this.s = new Array(n + 1).fill(0);
    for (let i = 0; i < n; ++i) {
        this.s[i + 1] = this.s[i] + w[i];
    }
};

/**
 * @return {number}
 */
Solution.prototype.pickIndex = function () {
    const n = this.s.length;
    const x = 1 + Math.floor(Math.random() * this.s[n - 1]);
    let left = 1,
        right = n - 1;
    while (left < right) {
        const mid = (left + right) >> 1;
        if (this.s[mid] >= x) {
            right = mid;
        } else {
            left = mid + 1;
        }
    }
    return left - 1;
};

/**
 * Your Solution object will be instantiated and called as such:
 * var obj = new Solution(w)
 * var param_1 = obj.pickIndex()
 */

528. 按权重随机选择

题目描述

解法

方法一

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