树
深度优先搜索
广度优先搜索
二叉搜索树
二叉树
题目描述
给你一个二叉搜索树的根节点 root
,返回 树中任意两不同节点值之间的最小差值 。
差值是一个正数,其数值等于两值之差的绝对值。
示例 1:
输入: root = [4,2,6,1,3]
输出: 1
示例 2:
输入: root = [1,0,48,null,null,12,49]
输出: 1
提示:
树中节点的数目范围是 [2, 104 ]
0 <= Node.val <= 105
注意: 本题与 783 https://leetcode.cn/problems/minimum-distance-between-bst-nodes/ 相同
解法
方法一:中序遍历
中序遍历二叉搜索树,获取当前节点与上个节点差值的最小值即可。
Python3 Java C++ Go Rust TypeScript
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20 # Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution :
def getMinimumDifference ( self , root : TreeNode ) -> int :
def dfs ( root ):
if root is None :
return
dfs ( root . left )
nonlocal ans , prev
ans = min ( ans , abs ( prev - root . val ))
prev = root . val
dfs ( root . right )
ans = prev = inf
dfs ( root )
return ans
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37 /**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private int ans ;
private int prev ;
private int inf = Integer . MAX_VALUE ;
public int getMinimumDifference ( TreeNode root ) {
ans = inf ;
prev = inf ;
dfs ( root );
return ans ;
}
private void dfs ( TreeNode root ) {
if ( root == null ) {
return ;
}
dfs ( root . left );
ans = Math . min ( ans , Math . abs ( root . val - prev ));
prev = root . val ;
dfs ( root . right );
}
}
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31 /**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public :
const int inf = INT_MAX ;
int ans ;
int prev ;
int getMinimumDifference ( TreeNode * root ) {
ans = inf , prev = inf ;
dfs ( root );
return ans ;
}
void dfs ( TreeNode * root ) {
if ( ! root ) return ;
dfs ( root -> left );
ans = min ( ans , abs ( prev - root -> val ));
prev = root -> val ;
dfs ( root -> right );
}
};
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31 /**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func getMinimumDifference ( root * TreeNode ) int {
inf := 0x3f3f3f3f
ans , prev := inf , inf
var dfs func ( * TreeNode )
dfs = func ( root * TreeNode ) {
if root == nil {
return
}
dfs ( root . Left )
ans = min ( ans , abs ( prev - root . Val ))
prev = root . Val
dfs ( root . Right )
}
dfs ( root )
return ans
}
func abs ( x int ) int {
if x < 0 {
return - x
}
return x
}
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44 // Definition for a binary tree node.
// #[derive(Debug, PartialEq, Eq)]
// pub struct TreeNode {
// pub val: i32,
// pub left: Option<Rc<RefCell<TreeNode>>>,
// pub right: Option<Rc<RefCell<TreeNode>>>,
// }
//
// impl TreeNode {
// #[inline]
// pub fn new(val: i32) -> Self {
// TreeNode {
// val,
// left: None,
// right: None
// }
// }
// }
use std :: rc :: Rc ;
use std :: cell :: RefCell ;
impl Solution {
#[allow(dead_code)]
pub fn get_minimum_difference ( root : Option < Rc < RefCell < TreeNode >>> ) -> i32 {
let mut ret = i32 :: MAX ;
let mut prev = i32 :: MAX ;
Self :: traverse ( root , & mut prev , & mut ret );
ret
}
#[allow(dead_code)]
fn traverse ( root : Option < Rc < RefCell < TreeNode >>> , prev : & mut i32 , ans : & mut i32 ) {
let left = root . as_ref (). unwrap (). borrow (). left . clone ();
let right = root . as_ref (). unwrap (). borrow (). right . clone ();
let val = root . as_ref (). unwrap (). borrow (). val ;
if ! left . is_none () {
Self :: traverse ( left . clone (), prev , ans );
}
* ans = std :: cmp :: min ( * ans , ( * prev - val ). abs ());
* prev = val ;
if ! right . is_none () {
Self :: traverse ( right . clone (), prev , ans );
}
}
}
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32 /**
* Definition for a binary tree node.
* class TreeNode {
* val: number
* left: TreeNode | null
* right: TreeNode | null
* constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
* }
*/
function getMinimumDifference ( root : TreeNode | null ) : number {
if ( ! root ) return 0 ;
let prev = Number . MIN_SAFE_INTEGER ;
let min = Number . MAX_SAFE_INTEGER ;
const dfs = ( node : TreeNode | null ) => {
if ( ! node ) return ;
dfs ( node . left );
min = Math . min ( min , node . val - prev );
prev = node . val ;
dfs ( node . right );
};
dfs ( root );
return min ;
}