16.02. Words Frequency

Description

Design a method to find the frequency of occurrences of any given word in a book. What if we were running this algorithm multiple times?

You should implement following methods:

WordsFrequency(book) constructor, parameter is a array of strings, representing the book.
get(word) get the frequency of word in the book.

Example:


WordsFrequency wordsFrequency = new WordsFrequency({"i", "have", "an", "apple", "he", "have", "a", "pen"});

wordsFrequency.get("you"); //returns 0，"you" is not in the book

wordsFrequency.get("have"); //returns 2，"have" occurs twice in the book

wordsFrequency.get("an"); //returns 1

wordsFrequency.get("apple"); //returns 1

wordsFrequency.get("pen"); //returns 1

Note:

There are only lowercase letters in book[i].
1 <= book.length <= 100000
1 <= book[i].length <= 10
get function will not be called more than 100000 times.

Solutions

Solution 1: Hash Table

We use a hash table $cnt$ to count the number of occurrences of each word in $book$.

When calling the get function, we only need to return the number of occurrences of the corresponding word in $cnt$.

In terms of time complexity, the time complexity of initializing the hash table $cnt$ is $O(n)$, where $n$ is the length of $book$. The time complexity of the get function is $O(1)$. The space complexity is $O(n)$.

Python3JavaC++GoTypeScriptRustJavaScriptSwift

class WordsFrequency:
    def __init__(self, book: List[str]):
        self.cnt = Counter(book)

    def get(self, word: str) -> int:
        return self.cnt[word]


# Your WordsFrequency object will be instantiated and called as such:
# obj = WordsFrequency(book)
# param_1 = obj.get(word)

class WordsFrequency {
    private Map<String, Integer> cnt = new HashMap<>();

    public WordsFrequency(String[] book) {
        for (String x : book) {
            cnt.merge(x, 1, Integer::sum);
        }
    }

    public int get(String word) {
        return cnt.getOrDefault(word, 0);
    }
}

/**
 * Your WordsFrequency object will be instantiated and called as such:
 * WordsFrequency obj = new WordsFrequency(book);
 * int param_1 = obj.get(word);
 */

class WordsFrequency {
public:
    WordsFrequency(vector<string>& book) {
        for (auto& x : book) {
            ++cnt[x];
        }
    }

    int get(string word) {
        return cnt[word];
    }

private:
    unordered_map<string, int> cnt;
};

/**
 * Your WordsFrequency object will be instantiated and called as such:
 * WordsFrequency* obj = new WordsFrequency(book);
 * int param_1 = obj->get(word);
 */

type WordsFrequency struct {
    cnt map[string]int
}

func Constructor(book []string) WordsFrequency {
    cnt := map[string]int{}
    for _, x := range book {
        cnt[x]++
    }
    return WordsFrequency{cnt}
}

func (this *WordsFrequency) Get(word string) int {
    return this.cnt[word]
}

/**
 * Your WordsFrequency object will be instantiated and called as such:
 * obj := Constructor(book);
 * param_1 := obj.Get(word);
 */

class WordsFrequency {
    private cnt: Map<string, number>;

    constructor(book: string[]) {
        const cnt = new Map<string, number>();
        for (const word of book) {
            cnt.set(word, (cnt.get(word) ?? 0) + 1);
        }
        this.cnt = cnt;
    }

    get(word: string): number {
        return this.cnt.get(word) ?? 0;
    }
}

/**
 * Your WordsFrequency object will be instantiated and called as such:
 * var obj = new WordsFrequency(book)
 * var param_1 = obj.get(word)
 */

use std::collections::HashMap;
struct WordsFrequency {
    cnt: HashMap<String, i32>,
}

/**
 * `&self` means the method takes an immutable reference.
 * If you need a mutable reference, change it to `&mut self` instead.
 */
impl WordsFrequency {
    fn new(book: Vec<String>) -> Self {
        let mut cnt = HashMap::new();
        for word in book.into_iter() {
            *cnt.entry(word).or_insert(0) += 1;
        }
        Self { cnt }
    }

    fn get(&self, word: String) -> i32 {
        *self.cnt.get(&word).unwrap_or(&0)
    }
}

/**
 * @param {string[]} book
 */
var WordsFrequency = function (book) {
    this.cnt = new Map();
    for (const x of book) {
        this.cnt.set(x, (this.cnt.get(x) || 0) + 1);
    }
};

/**
 * @param {string} word
 * @return {number}
 */
WordsFrequency.prototype.get = function (word) {
    return this.cnt.get(word) || 0;
};

/**
 * Your WordsFrequency object will be instantiated and called as such:
 * var obj = new WordsFrequency(book)
 * var param_1 = obj.get(word)
 */

class WordsFrequency {
    private var cnt: [String: Int] = [:]

    init(_ book: [String]) {
        for word in book {
            cnt[word, default: 0] += 1
        }
    }

    func get(_ word: String) -> Int {
        return cnt[word, default: 0]
    }
}

16.02. Words Frequency

Description

Solutions

Solution 1: Hash Table

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