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16.15. Master Mind

Description

The Game of Master Mind is played as follows:

The computer has four slots, and each slot will contain a ball that is red (R). yellow (Y). green (G) or blue (B). For example, the computer might have RGGB (Slot #1 is red, Slots #2 and #3 are green, Slot #4 is blue).

You, the user, are trying to guess the solution. You might, for example, guess YRGB.

When you guess the correct color for the correct slot, you get a "hit:' If you guess a color that exists but is in the wrong slot, you get a "pseudo-hit:' Note that a slot that is a hit can never count as a pseudo-hit.

For example, if the actual solution is RGBY and you guess GGRR, you have one hit and one pseudo-hit. Write a method that, given a guess and a solution, returns the number of hits and pseudo-hits.

Given a sequence of colors solution, and a guess, write a method that return the number of hits and pseudo-hit answer, where answer[0] is the number of hits and answer[1] is the number of pseudo-hit.

Example:


Input:  solution="RGBY",guess="GGRR"

Output:  [1,1]

Explanation:  hit once, pseudo-hit once.

Note:

  • len(solution) = len(guess) = 4
  • There are only "R","G","B","Y" in solution and guess.

Solutions

Solution 1: Hash Table

We simultaneously traverse both strings, count the number of corresponding characters that are the same, and accumulate them in $x$. Then we record the characters and their frequencies in both strings in hash tables $cnt1$ and $cnt2$, respectively.

Next, we traverse both hash tables, count the number of common characters, and accumulate them in $y$. The answer is then $[x, y - x]$.

The time complexity is $O(C)$, and the space complexity is $O(C)$. Here, $C=4$ for this problem.

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class Solution:
    def masterMind(self, solution: str, guess: str) -> List[int]:
        x = sum(a == b for a, b in z