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912. Sort an Array

Description

Given an array of integers nums, sort the array in ascending order and return it.

You must solve the problem without using any built-in functions in O(nlog(n)) time complexity and with the smallest space complexity possible.

 

Example 1:

Input: nums = [5,2,3,1]
Output: [1,2,3,5]
Explanation: After sorting the array, the positions of some numbers are not changed (for example, 2 and 3), while the positions of other numbers are changed (for example, 1 and 5).

Example 2:

Input: nums = [5,1,1,2,0,0]
Output: [0,0,1,1,2,5]
Explanation: Note that the values of nums are not necessairly unique.

 

Constraints:

  • 1 <= nums.length <= 5 * 104
  • -5 * 104 <= nums[i] <= 5 * 104

Solutions

Solution 1

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class Solution:
    def sortArray(self, nums: List[int]) -> List[int]:
        def quick_sort(l, r):
            if l >= r:
                return
            x = nums[randint(l, r)]
            i, j, k = l - 1, r + 1, l
            while k < j:
                if nums[k] < x:
                    nums[i + 1], nums[k] = nums[k], nums[i + 1]
                    i, k = i + 1, k + 1
                elif nums[k] > x:
                    j -= 1
                    nums[j], nums[k] = nums[k], nums[j]
                else:
                    k = k + 1
            quick_sort(l, i)
            quick_sort(j, r)

        quick_sort(0, len(nums) - 1)
        return nums

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class Solution {
    private int[] nums;

    public int[] sortArray(int[] nums) {
        this.nums = nums;
        quikcSort(0, nums.length - 1);
        return nums;
    }

    private void quikcSort(int l, int r) {
        if (l >= r) {
            return;
        }
        int x = nums[(l + r) >> 1];
        int i = l - 1, j = r + 1;
        while (i < j) {
            while (nums[++i] < x) {
            }
            while (nums[--j] > x) {
            }
            if (i < j) {
                int t = nums[i];
                nums[i] = nums[j];
                nums[j] = t;
            }
        }
        quikcSort(l, j);
        quikcSort(j + 1, r);
    }
}

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class Solution {
public:
    vector<int> sortArray(vector<int>& nums) {
        function<void(int, int)> quick_sort = [&](int l, int r) {
            if (l >= r) {
                return;
            }
            int i = l - 1, j = r + 1;
            int x = nums[(l + r) >> 1];
            while (i < j) {
                while (nums[++i] < x) {
                }
                while (nums[--j] > x) {
                }
                if (i < j) {
                    swap(nums[i], nums[j]);
                }
            }
            quick_sort(l, j);
            quick_sort(j + 1, r);
        };
        quick_sort(0, nums.size() - 1);
        return nums;
    }
};

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func sortArray(nums []int) []int {
    quickSort(nums, 0, len(nums)-1)
    return nums
}

func quickSort(nums []int, l, r int) {
    if l >= r {
        return
    }
    i, j := l-1, r+1
    x := nums[(l+r)>>1]
    for i < j {
        for {
            i++
            if nums[i] >= x {
                break
            }
        }
        for {
            j--
            if nums[j] <= x {
                break
            }
        }
        if i < j {
            nums[i], nums[j] = nums[j], nums[i]
        }
    }
    quickSort(nums, l, j)
    quickSort(nums, j+1, r)
}

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function sortArray(nums: number[]): number[] {
    function quickSort(l: number, r: number) {
        if (l >= r) {
            return;
        }
        let i = l - 1;
        let j = r + 1;
        const x = nums[(l + r) >> 1];
        while (i < j) {
            while (nums[++i] < x);
            while (nums[--j] > x);
            if (i < j) {
                [nums[i], nums[j]] = [nums[j], nums[i]];
            }
        }
        quickSort(l, j);
        quickSort(j + 1, r);
    }
    const n = nums.length;
    quickSort(0, n - 1);
    return nums;
}

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/**
 * @param {number[]} nums
 * @return {number[]}
 */
var sortArray = function (nums) {
    function quickSort(l, r) {
        if (l >= r) {
            return;
        }
        let i = l - 1;
        let j = r + 1;
        const x = nums[(l + r) >> 1];
        while (i < j) {
            while (nums[++i] < x);
            while (nums[--j] > x);
            if (i < j) {
                [nums[i], nums[j]] = [nums[j], nums[i]];
            }
        }
        quickSort(l, j);
        quickSort(j + 1, r);
    }
    const n = nums.length;
    quickSort(0, n - 1);
    return nums;
};

Solution 2

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class Solution:
    def sortArray(self, nums: List[int]) -> List[int]:
        def merge_sort(l, r):
            if l >= r:
                return
            mid = (l + r) >> 1
            merge_sort(l, mid)
            merge_sort(mid + 1, r)
            i, j = l, mid + 1
            tmp = []
            while i <= mid and j <= r:
                if nums[i] <= nums[j]:
                    tmp.append(nums[i])
                    i += 1
                else:
                    tmp.append(nums[j])
                    j += 1
            if i <= mid:
                tmp.extend(nums[i : mid + 1])
            if j <= r:
                tmp.extend(nums[j : r + 1])
            for i in range(l, r + 1):
                nums[i] = tmp[i - l]

        merge_sort(0, len(nums) - 1)
        return nums

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class Solution {
    private int[] nums;

    public int[] sortArray(int[] nums) {
        this.nums = nums;
        quickSort(0, nums.length - 1);
        return nums;
    }

    private void quickSort(int l, int r) {
        if (l >= r) {
            return;
        }
        int i = l - 1, j = r + 1, k = l;
        int x = nums[(l + r) >> 1];
        while (k < j) {
            if (nums[k] < x) {
                swap(++i, k++);
            } else if (nums[k] > x) {
                swap(--j, k);
            } else {
                ++k;
            }
        }
        quickSort(l, i);
        quickSort(j, r);
    }

    private void swap(int i, int j) {
        int t = nums[i];
        nums[i] = nums[j];
        nums[j] = t;
    }
}

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class Solution {
public:
    vector<int> sortArray(vector<int>& nums) {
        function<void(int, int)> merge_sort = [&](int l, int r) {
            if (l >= r) {
                return;
            }
            int mid = (l + r) >> 1;
            merge_sort(l, mid);
            merge_sort(mid + 1, r);
            int i = l, j = mid + 1, k = 0;
            int tmp[r - l + 1];
            while (i <= mid && j <= r) {
                if (nums[i] <= nums[j]) {
                    tmp[k++] = nums[i++];
                } else {
                    tmp[k++] = nums[j++];
                }
            }
            while (i <= mid) {
                tmp[k++] = nums[i++];
            }
            while (j <= r) {
                tmp[k++] = nums[j++];
            }
            for (i = l; i <= r; ++i) {
                nums[i] = tmp[i - l];
            }
        };
        merge_sort(0, nums.size() - 1);
        return nums;
    }
};

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func sortArray(nums []int) []int {
    mergeSort(nums, 0, len(nums)-1)
    return nums
}

func mergeSort(nums []int, l, r int) {
    if l >= r {
        return
    }
    mid := (l + r) >> 1
    mergeSort(nums, l, mid)
    mergeSort(nums, mid+1, r)
    i, j, k := l, mid+1, 0
    tmp := make([]int, r-l+1)
    for i <= mid && j <= r {
        if nums[i] <= nums[j] {
            tmp[k] = nums[i]
            i++
        } else {
            tmp[k] = nums[j]
            j++
        }
        k++
    }
    for ; i <= mid; i++ {
        tmp[k] = nums[i]
        k++
    }
    for ; j <= r; j++ {
        tmp[k] = nums[j]
        k++
    }
    for i = l; i <= r; i++ {
        nums[i] = tmp[i-l]
    }
}

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function sortArray(nums: number[]): number[] {
    function mergetSort(l: number, r: number) {
        if (l >= r) {
            return;
        }
        const mid = (l + r) >> 1;
        mergetSort(l, mid);
        mergetSort(mid + 1, r);
        let [i, j, k] = [l, mid + 1, 0];
        while (i <= mid && j <= r) {
            if (nums[i] <= nums[j]) {
                tmp[k++] = nums[i++];
            } else {
                tmp[k++] = nums[j++];
            }
        }
        while (i <= mid) {
            tmp[k++] = nums[i++];
        }
        while (j <= r) {
            tmp[k++] = nums[j++];
        }
        for (i = l, j = 0; i <= r; ++i, ++j) {
            nums[i] = tmp[j];
        }
    }
    const n = nums.length;
    let tmp = new Array(n).fill(0);
    mergetSort(0, n - 1);
    return nums;
}

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/**
 * @param {number[]} nums
 * @return {number[]}
 */
var sortArray = function (nums) {
    function mergetSort(l, r) {
        if (l >= r) {
            return;
        }
        const mid = (l + r) >> 1;
        mergetSort(l, mid);
        mergetSort(mid + 1, r);
        let [i, j, k] = [l, mid + 1, 0];
        while (i <= mid && j <= r) {
            if (nums[i] <= nums[j]) {
                tmp[k++] = nums[i++];
            } else {
                tmp[k++] = nums[j++];
            }
        }
        while (i <= mid) {
            tmp[k++] = nums[i++];
        }
        while (j <= r) {
            tmp[k++] = nums[j++];
        }
        for (i = l, j = 0; i <= r; ++i, ++j) {
            nums[i] = tmp[j];
        }
    }
    const n = nums.length;
    let tmp = new Array(n).fill(0);
    mergetSort(0, n - 1);
    return nums;
};

Solution 3

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class Solution {
    private int[] nums;

    public int[] sortArray(int[] nums) {
        this.nums = nums;
        mergeSort(0, nums.length - 1);
        return nums;
    }

    private void mergeSort(int l, int r) {
        if (l >= r) {
            return;
        }
        int mid = (l + r) >> 1;
        mergeSort(l, mid);
        mergeSort(mid + 1, r);
        int i = l, j = mid + 1, k = 0;
        int[] tmp = new int[r - l + 1];
        while (i <= mid && j <= r) {
            if (nums[i] <= nums[j]) {
                tmp[k++] = nums[i++];
            } else {
                tmp[k++] = nums[j++];
            }
        }
        while (i <= mid) {
            tmp[k++] = nums[i++];
        }
        while (j <= r) {
            tmp[k++] = nums[j++];
        }
        for (i = l; i <= r; ++i) {
            nums[i] = tmp[i - l];
        }
    }
}

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