165. Compare Version Numbers
Description
Given two version strings, version1
and version2
, compare them. A version string consists of revisions separated by dots '.'
. The value of the revision is its integer conversion ignoring leading zeros.
To compare version strings, compare their revision values in left-to-right order. If one of the version strings has fewer revisions, treat the missing revision values as 0
.
Return the following:
- If
version1 < version2
, return -1. - If
version1 > version2
, return 1. - Otherwise, return 0.
Example 1:
Input: version1 = "1.2", version2 = "1.10"
Output: -1
Explanation:
version1's second revision is "2" and version2's second revision is "10": 2 < 10, so version1 < version2.
Example 2:
Input: version1 = "1.01", version2 = "1.001"
Output: 0
Explanation:
Ignoring leading zeroes, both "01" and "001" represent the same integer "1".
Example 3:
Input: version1 = "1.0", version2 = "1.0.0.0"
Output: 0
Explanation:
version1 has less revisions, which means every missing revision are treated as "0".
Constraints:
1 <= version1.length, version2.length <= 500
version1
andversion2
only contain digits and'.'
.version1
andversion2
are valid version numbers.- All the given revisions in
version1
andversion2
can be stored in a 32-bit integer.
Solutions
Solution 1
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 |
|