Description
Given the head
of a linked list and an integer val
, remove all the nodes of the linked list that has Node.val == val
, and return the new head.
Example 1:
Input: head = [1,2,6,3,4,5,6], val = 6
Output: [1,2,3,4,5]
Example 2:
Input: head = [], val = 1
Output: []
Example 3:
Input: head = [7,7,7,7], val = 7
Output: []
Constraints:
- The number of nodes in the list is in the range
[0, 104]
.
1 <= Node.val <= 50
0 <= val <= 50
Solutions
Solution 1
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15 | # Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def removeElements(self, head: ListNode, val: int) -> ListNode:
dummy = ListNode(-1, head)
pre = dummy
while pre.next:
if pre.next.val != val:
pre = pre.next
else:
pre.next = pre.next.next
return dummy.next
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23 | /**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode removeElements(ListNode head, int val) {
ListNode dummy = new ListNode(-1, head);
ListNode pre = dummy;
while (pre.next != null) {
if (pre.next.val != val)
pre = pre.next;
else
pre.next = pre.next.next;
}
return dummy.next;
}
}
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16 | class Solution {
public:
ListNode* removeElements(ListNode* head, int val) {
ListNode* dummy = new ListNode();
dummy->next = head;
ListNode* p = dummy;
while (p->next) {
if (p->next->val == val) {
p->next = p->next->next;
} else {
p = p->next;
}
}
return dummy->next;
}
};
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13 | func removeElements(head *ListNode, val int) *ListNode {
dummy := new(ListNode)
dummy.Next = head
p := dummy
for p.Next != nil {
if p.Next.Val == val {
p.Next = p.Next.Next
} else {
p = p.Next
}
}
return dummy.Next
}
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24 | /**
* Definition for singly-linked list.
* class ListNode {
* val: number
* next: ListNode | null
* constructor(val?: number, next?: ListNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
* }
*/
function removeElements(head: ListNode | null, val: number): ListNode | null {
const dummy: ListNode = new ListNode(0, head);
let cur: ListNode = dummy;
while (cur.next != null) {
if (cur.next.val === val) {
cur.next = cur.next.next;
} else {
cur = cur.next;
}
}
return dummy.next;
}
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31 | // Definition for singly-linked list.
// #[derive(PartialEq, Eq, Clone, Debug)]
// pub struct ListNode {
// pub val: i32,
// pub next: Option<Box<ListNode>>
// }
//
// impl ListNode {
// #[inline]
// fn new(val: i32) -> Self {
// ListNode {
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