Skip to content

647. Palindromic Substrings

Description

Given a string s, return the number of palindromic substrings in it.

A string is a palindrome when it reads the same backward as forward.

A substring is a contiguous sequence of characters within the string.

 

Example 1:

Input: s = "abc"
Output: 3
Explanation: Three palindromic strings: "a", "b", "c".

Example 2:

Input: s = "aaa"
Output: 6
Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".

 

Constraints:

  • 1 <= s.length <= 1000
  • s consists of lowercase English letters.

Solutions

Solution 1

1
2
3
4
5
6
7
8
9
class Solution:
    def countSubstrings(self, s: str) -> int:
        ans, n = 0, len(s)
        for k in range(n * 2 - 1):
            i, j = k // 2, (k + 1) // 2
            while ~i and j < n and s[i] == s[j]:
                ans += 1
                i, j = i - 1, j + 1
        return ans

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
class Solution {
    public int countSubstrings(String s) {
        int ans = 0;
        int n = s.length();
        for (int k = 0; k < n * 2 - 1; ++k) {
            int i = k / 2, j = (k + 1) / 2;
            while (i >= 0 && j < n && s.charAt(i) == s.charAt(j)) {
                ++ans;
                --i;
                ++j;
            }
        }
        return ans;
    }
}

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
class Solution {
public:
    int countSubstrings(string s) {
        int ans = 0;
        int n = s.size();
        for (int k = 0; k < n * 2 - 1; ++k) {
            int i = k / 2, j = (k + 1) / 2;
            while (~i && j < n && s[i] == s[j]) {
                ++ans;
                --i;
                ++j;
            }
        }
        return ans;
    }
};

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
func countSubstrings(s string) int {
    ans, n := 0, len(s)
    for k := 0; k < n*2-1; k++ {
        i, j := k/2, (k+1)/2
        for i >= 0 && j < n && s[i] == s[j] {
            ans++
            i, j = i-1, j+1
        }
    }
    return ans
}

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
/**
 * @param {string} s
 * @return {number}
 */
var countSubstrings = function (s) {
    let ans = 0;
    const n = s.length;
    for (let k = 0; k < n * 2 - 1; ++k) {
        let i = k >> 1;
        let j = (k + 1) >> 1;
        while (~i && j < n && s[i] == s[j]) {
            ++ans;
            --i;
            ++j;
        }
    }
    return ans;
};

Solution 2