Description
Given two strings s
and goal
, return true
if you can swap two letters in s
so the result is equal to goal
, otherwise, return false
.
Swapping letters is defined as taking two indices i
and j
(0-indexed) such that i != j
and swapping the characters at s[i]
and s[j]
.
- For example, swapping at indices
0
and 2
in "abcd"
results in "cbad"
.
Example 1:
Input: s = "ab", goal = "ba"
Output: true
Explanation: You can swap s[0] = 'a' and s[1] = 'b' to get "ba", which is equal to goal.
Example 2:
Input: s = "ab", goal = "ab"
Output: false
Explanation: The only letters you can swap are s[0] = 'a' and s[1] = 'b', which results in "ba" != goal.
Example 3:
Input: s = "aa", goal = "aa"
Output: true
Explanation: You can swap s[0] = 'a' and s[1] = 'a' to get "aa", which is equal to goal.
Constraints:
1 <= s.length, goal.length <= 2 * 104
s
and goal
consist of lowercase letters.
Solutions
Solution 1
| class Solution:
def buddyStrings(self, s: str, goal: str) -> bool:
m, n = len(s), len(goal)
if m != n:
return False
cnt1, cnt2 = Counter(s), Counter(goal)
if cnt1 != cnt2:
return False
diff = sum(s[i] != goal[i] for i in range(n))
return diff == 2 or (diff == 0 and any(v > 1 for v in cnt1.values()))
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29 | class Solution {
public boolean buddyStrings(String s, String goal) {
int m = s.length(), n = goal.length();
if (m != n) {
return false;
}
int diff = 0;
int[] cnt1 = new int[26];
int[] cnt2 = new int[26];
for (int i = 0; i < n; ++i) {
int a = s.charAt(i), b = goal.charAt(i);
++cnt1[a - 'a'];
++cnt2[b - 'a'];
if (a != b) {
++diff;
}
}
boolean f = false;
for (int i = 0; i < 26; ++i) {
if (cnt1[i] != cnt2[i]) {
return false;
}
if (cnt1[i] > 1) {
f = true;
}
}
return diff == 2 || (diff == 0 && f);
}
}
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21 | class Solution {
public:
bool buddyStrings(string s, string goal) {
int m = s.size(), n = goal.size();
if (m != n) return false;
int diff = 0;
vector<int> cnt1(26);
vector<int> cnt2(26);
for (int i = 0; i < n; ++i) {
++cnt1[s[i] - 'a'];
++cnt2[goal[i] - 'a'];
if (s[i] != goal[i]) ++diff;
}
bool f = false;
for (int i = 0; i < 26; ++i) {
if (cnt1[i] != cnt2[i]) return false;
if (cnt1[i] > 1) f = true;
}
return diff == 2 || (diff == 0 && f);
}
};
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26 | func buddyStrings(s string
|