367. Valid Perfect Square
Description
Given a positive integer num, return true
if num
is a perfect square or false
otherwise.
A perfect square is an integer that is the square of an integer. In other words, it is the product of some integer with itself.
You must not use any built-in library function, such as sqrt
.
Example 1:
Input: num = 16 Output: true Explanation: We return true because 4 * 4 = 16 and 4 is an integer.
Example 2:
Input: num = 14 Output: false Explanation: We return false because 3.742 * 3.742 = 14 and 3.742 is not an integer.
Constraints:
1 <= num <= 231 - 1
Solutions
Solution 1: Binary Search
We can use binary search to solve this problem. Define the left boundary $l = 1$ and the right boundary $r = num$ of the binary search, then find the smallest integer $x$ that satisfies $x^2 \geq num$ in the range $[l, r]$. Finally, if $x^2 = num$, then $num$ is a perfect square.
The time complexity is $O(\log n)$, where $n$ is the given number. The space complexity is $O(1)$.
1 2 3 4 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
|
1 2 3 4 |
|
1 2 3 4 5 6 7 8 9 10 11 12 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
|
Solution 2: Mathematics
Since $1 + 3 + 5 + \cdots + (2n - 1) = n^2$, we can gradually subtract $1, 3, 5, \cdots$ from $num$. If $num$ finally equals $0$, then $num$ is a perfect square.
The time complexity is $O(\sqrt n)$, and the space complexity is $O(1)$.
1 2 3 < |