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1668. Maximum Repeating Substring

Description

For a string sequence, a string word is k-repeating if word concatenated k times is a substring of sequence. The word's maximum k-repeating value is the highest value k where word is k-repeating in sequence. If word is not a substring of sequence, word's maximum k-repeating value is 0.

Given strings sequence and word, return the maximum k-repeating value of word in sequence.

 

Example 1:

Input: sequence = "ababc", word = "ab"
Output: 2
Explanation: "abab" is a substring in "ababc".

Example 2:

Input: sequence = "ababc", word = "ba"
Output: 1
Explanation: "ba" is a substring in "ababc". "baba" is not a substring in "ababc".

Example 3:

Input: sequence = "ababc", word = "ac"
Output: 0
Explanation: "ac" is not a substring in "ababc". 

 

Constraints:

  • 1 <= sequence.length <= 100
  • 1 <= word.length <= 100
  • sequence and word contains only lowercase English letters.

Solutions

Solution 1

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class Solution:
    def maxRepeating(self, sequence: str, word: str) -> int:
        for k in range(len(sequence) // len(word), -1, -1):
            if word * k in sequence:
                return k
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class Solution {
    public int maxRepeating(String sequence, String word) {
        for (int k = sequence.length() / word.length(); k > 0; --k) {
            if (sequence.contains(word.repeat(k))) {
                return k;
            }
        }
        return 0;
    }
}
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class Solution {
public:
    int maxRepeating(string sequence, string word) {
        int ans = 0;
        string t = word;
        int x = sequence.size() / word.size();
        for (int k = 1; k <= x; ++k) {
            // C++ θΏ™ι‡Œδ»Žε°εˆ°ε€§ζžšδΈΎι‡ε€ε€Ό
            if (sequence.find(t) != string::npos) {
                ans = k;
            }
            t += word;
        }
        return ans;
    }
};
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func maxRepeating(sequence string, word string) int {
    for k := len(sequence) / len(word); k > 0; k-- {
        if strings.Contains(sequence, strings.Repeat(word, k)) {
            return k
        }
    }
    return 0
}
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function maxRepeating(sequence: string, word: string): number {
    let n = sequence.length;
    let m = word.length;
    for (let k = Math.floor(n / m); k > 0; k--) {
        if (sequence.includes(word.repeat(k))) {
            return k;
        }
    }
    return 0;
}
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impl Solution {
    pub fn max_repeating(sequence: String, word: String) -> i32 {
        let n = sequence.len();
        let m = word.len();
        if n < m {
            return 0;
        }
        let mut dp = vec![0; n - m + 1];
        for i in 0..=n - m {
            let s = &sequence[i..i + m];
            if s == word {
                dp[i] = (if (i as i32) - (m as i32) < 0 {
                    0
                } else<