Depth-First Search
Breadth-First Search
Array
Matrix
Description
You are given an image represented by an m x n
grid of integers image
, where image[i][j]
represents the pixel value of the image. You are also given three integers sr
, sc
, and color
. Your task is to perform a flood fill on the image starting from the pixel image[sr][sc]
.
To perform a flood fill :
Begin with the starting pixel and change its color to color
.
Perform the same process for each pixel that is directly adjacent (pixels that share a side with the original pixel, either horizontally or vertically) and shares the same color as the starting pixel.
Keep repeating this process by checking neighboring pixels of the updated pixels and modifying their color if it matches the original color of the starting pixel.
The process stops when there are no more adjacent pixels of the original color to update.
Return the modified image after performing the flood fill.
Example 1:
Input: image = [[1,1,1],[1,1,0],[1,0,1]], sr = 1, sc = 1, color = 2
Output: [[2,2,2],[2,2,0],[2,0,1]]
Explanation:
From the center of the image with position (sr, sc) = (1, 1)
(i.e., the red pixel), all pixels connected by a path of the same color as the starting pixel (i.e., the blue pixels) are colored with the new color.
Note the bottom corner is not colored 2, because it is not horizontally or vertically connected to the starting pixel.
Example 2:
Input: image = [[0,0,0],[0,0,0]], sr = 0, sc = 0, color = 0
Output: [[0,0,0],[0,0,0]]
Explanation:
The starting pixel is already colored with 0, which is the same as the target color. Therefore, no changes are made to the image.
Constraints:
m == image.length
n == image[i].length
1 <= m, n <= 50
0 <= image[i][j], color < 216
0 <= sr < m
0 <= sc < n
Solutions
Solution 1
Python3 Java C++ Go TypeScript Rust
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21 class Solution :
def floodFill (
self , image : List [ List [ int ]], sr : int , sc : int , color : int
) -> List [ List [ int ]]:
def dfs ( i , j ):
if (
not 0 <= i < m
or not 0 <= j < n
or image [ i ][ j ] != oc
or image [ i ][ j ] == color
):
return
image [ i ][ j ] = color
for a , b in pairwise ( dirs ):
dfs ( i + a , j + b )
dirs = ( - 1 , 0 , 1 , 0 , - 1 )
m , n = len ( image ), len ( image [ 0 ])
oc = image [ sr ][ sc ]
dfs ( sr , sc )
return image
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25 class Solution {
private int [] dirs = { - 1 , 0 , 1 , 0 , - 1 };
private int [][] image ;
private int nc ;
private int oc ;
public int [][] floodFill ( int [][] image , int sr , int sc , int color ) {
nc = color ;
oc = image [ sr ][ sc ] ;
this . image = image ;
dfs ( sr , sc );
return image ;
}
private void dfs ( int i , int j ) {
if ( i < 0 || i >= image . length || j < 0 || j >= image [ 0 ] . length || image [ i ][ j ] != oc
|| image [ i ][ j ] == nc ) {
return ;
}
image [ i ][ j ] = nc ;
for ( int k = 0 ; k < 4 ; ++ k ) {
dfs ( i + dirs [ k ] , j + dirs [ k + 1 ] );
}
}
}
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19 class Solution {
public :
vector < vector < int >> floodFill ( vector < vector < int >>& image , int sr , int sc , int color ) {
int m = image . size (), n = image [ 0 ]. size ();
int oc = image [ sr ][ sc ];
int dirs [ 5 ] = { -1 , 0 , 1 , 0 , -1 };
function < void ( int , int ) > dfs = [ & ]( int i , int j ) {
if ( i < 0 || i >= m || j < 0 || j >= n || image [ i ][ j ] != oc || image [ i ][ j ] == color ) {
return ;
}
image [ i ][ j ] = color ;
for ( int k = 0 ; k < 4 ; ++ k ) {
dfs ( i + dirs [ k ], j + dirs [ k + 1 ]);
}
};
dfs ( sr , sc );
return image ;
}
};
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17 func floodFill ( image [][] int , sr int , sc int , color int ) [][] int {
oc := image [ sr ][ sc ]
m , n := len ( image ), len ( image [ 0 ])
dirs := [] int { - 1 , 0 , 1 , 0 , - 1 }
var dfs func ( i , j int )
dfs = func ( i , j int ) {
if i < 0 || i >= m || j < 0 || j >= n || image [ i ][ j ] != oc || image [ i ][ j ] == color {
return
}
image [ i ][ j ] = color
for k := 0 ; k < 4 ; k ++ {
dfs ( i + dirs [ k ], j + dirs [ k + 1 ])
}
}
dfs ( sr , sc )
return image
}
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24 function floodFill ( image : number [][], sr : number , sc : number , newColor : number ) : number [][] {
const m = image . length ;
const n = image [ 0 ]. length ;
const target = image [ sr ][ sc ];
const dfs = ( i : number , j : number ) => {
if (
i < 0 ||
i === m ||
j < 0 ||
j === n ||
image [ i ][ j ] !== target ||
image [ i ][ j ] === newColor
) {
return ;
}
image [ i ][ j ] = newColor ;
dfs ( i + 1 , j );
dfs ( i - 1 , j );
dfs ( i , j + 1 );
dfs ( i , j - 1 );
};
dfs ( sr , sc );
return image ;
}
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24 impl Solution {
fn dfs ( image : & mut Vec < Vec < i32 >> , sr : i32 , sc : i32 , new_color : i32 , target : i32 ) {
if sr < 0 || sr == ( image . len () as i32 ) || sc < 0 || sc == ( image [ 0 ]. len () as i32 ) {
return ;
}
let sr = sr as usize ;
let sc = sc as usize ;
if sr < 0 || image [ sr ][ sc ] == new_color || image [ sr ][ sc ] != target {
return ;
}
image [ sr ][ sc ] = new_color ;
let sr = sr as i32 ;
let sc = sc as i32 ;
Self :: dfs ( image , sr + 1 , sc , new_color , target );
Self :: dfs ( image , sr - 1 , sc , new_color , target );
Self :: dfs ( image , sr , sc + 1 , new_color , target );
Self :: dfs ( image , sr , sc - 1 , new_color , target );
}
pub fn flood_fill ( image : Vec < Vec < i32 >> , sr : i32 , sc : i32 , new_color : i32 ) -> Vec < Vec < i32 >> {
let target = image [ sr as usize ][ sc as usize ];
Self :: dfs ( & mut image , sr , sc , new_color , target );
image
}
}
Solution 2
Python3 Java C++ Go
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18 class Solution :
def floodFill (
self , image : List [ List [ int ]], sr : int , sc : int , color : int
) -> List [ List [ int ]]:
if image [ sr ][ sc ] == color :
return image
q = deque ([( sr , sc )])
oc = image [ sr ][ sc ]
image [ sr ][ sc ] = color
dirs = ( - 1 , 0 , 1 , 0 , - 1 )
while q :
i , j = q . popleft ()
for a , b in pairwise ( dirs ):
x , y = i + a , j + b
if 0 <= x < len ( image ) and 0 <= y < len ( image [ 0 ]) and image [ x ][ y ] == oc :
q . append (( x , y ))
image [ x ][ y ] = color
return image
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25 class Solution {
public int [][] floodFill ( int [][] image , int sr , int sc , int color ) {
if ( image [ sr ][ sc ] == color ) {
return image ;
}
Deque < int []> q = new ArrayDeque <> ();
q . offer ( new int [] { sr , sc });
int oc = image [ sr ][ sc ] ;
image [ sr ][ sc ] = color ;
int [] dirs = { - 1 , 0 , 1 , 0 , - 1 };
while ( ! q . isEmpty ()) {
int [] p = q . poll ();
int i = p [ 0 ] , j = p [ 1 ] ;
for ( int k = 0 ; k < 4 ; ++ k ) {
int x = i + dirs [ k ] , y = j + dirs [ k + 1 ] ;
if ( x >= 0 && x < image . length && y >= 0 && y < image [ 0 ] . length
&& image [ x ][ y ] == oc ) {
q . offer ( new int [] { x , y });
image [ x ][ y ] = color ;
}
}
}
return image ;
}
}
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24 class Solution {
public :
vector < vector < int >> floodFill ( vector < vector < int >>& image , int sr , int sc , int color ) {
if ( image [ sr ][ sc ] == color ) return image ;
int oc = image [ sr ][ sc ];
image [ sr ][ sc ] = color ;
queue < pair < int , int >> q ;
q . push ({ sr , sc });
int dirs [ 5 ] = { -1 , 0 , 1 , 0 , -1 };
while ( ! q . empty ()) {
auto [ a , b ] = q . front ();
q . pop ();
for ( int k = 0 ; k < 4 ; ++ k ) {
int x = a + dirs [ k ];
int y = b + dirs [ k + 1 ];
if ( x >= 0 && x < image . size () && y >= 0 && y < image [ 0 ]. size () && image [ x ][ y ] == oc ) {
q . push ({ x , y });
image [ x ][ y ] = color ;
}
}
}
return image ;
}
};
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21 func floodFill ( image [][] int , sr int , sc int , color int ) [][] int {
if image [ sr ][ sc ] == color {
return image
}
oc := image [ sr ][ sc ]
q := [][] int {[] int { sr , sc }}
image [ sr ][ sc ] = color
dirs := [] int { - 1 , 0 , 1 , 0 , - 1 }
for len ( q ) > 0 {
p := q [ 0 ]
q = q [ 1 :]
for k := 0 ; k < 4 ; k ++ {
x , y := p [ 0 ] + dirs [ k ], p [ 1 ] + dirs [ k + 1 ]
if x >= 0 && x < len ( image ) && y >= 0 && y < len ( image [ 0 ]) && image [ x ][ y ] == oc {
q = append ( q , [] int { x , y })
image [ x ][ y ] = color
}
}
}
return image
}