660. Remove 9 π
Description
Start from integer 1
, remove any integer that contains 9
such as 9
, 19
, 29
...
Now, you will have a new integer sequence [1, 2, 3, 4, 5, 6, 7, 8, 10, 11, ...]
.
Given an integer n
, return the nth
(1-indexed) integer in the new sequence.
Example 1:
Input: n = 9 Output: 10
Example 2:
Input: n = 10 Output: 11
Constraints:
1 <= n <= 8 * 108
Solutions
Solution 1
1 |
|
1 |
|
1 |
|
1 |
|