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616. Add Bold Tag in String πŸ”’

Description

You are given a string s and an array of strings words.

You should add a closed pair of bold tag <b> and </b> to wrap the substrings in s that exist in words.

  • If two such substrings overlap, you should wrap them together with only one pair of closed bold-tag.
  • If two substrings wrapped by bold tags are consecutive, you should combine them.

Return s after adding the bold tags.

 

Example 1:

Input: s = "abcxyz123", words = ["abc","123"]
Output: "<b>abc</b>xyz<b>123</b>"
Explanation: The two strings of words are substrings of s as following: "abcxyz123".
We add <b> before each substring and </b> after each substring.

Example 2:

Input: s = "aaabbb", words = ["aa","b"]
Output: "<b>aaabbb</b>"
Explanation: 
"aa" appears as a substring two times: "aaabbb" and "aaabbb".
"b" appears as a substring three times: "aaabbb", "aaabbb", and "aaabbb".
We add <b> before each substring and </b> after each substring: "<b>a<b>a</b>a</b><b>b</b><b>b</b><b>b</b>".
Since the first two <b>'s overlap, we merge them: "<b>aaa</b><b>b</b><b>b</b><b>b</b>".
Since now the four <b>'s are consecutive, we merge them: "<b>aaabbb</b>".

 

Constraints:

  • 1 <= s.length <= 1000
  • 0 <= words.length <= 100
  • 1 <= words[i].length <= 1000
  • s and words[i] consist of English letters and digits.
  • All the values of words are unique.

 

Note: This question is the same as 758. Bold Words in String.

Solutions

Solution 1

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class Trie:
    def __init__(self):
        self.children = [None] * 128
        self.is_end = False

    def insert(self, word):
        node = self
        for c in word:
            idx = ord(c)
            if node.children[idx] is None:
                node.children[idx] = Trie()
            node = node.children[idx]
        node.is_end = True


class Solution:
    def addBoldTag(self, s: str, words: List[str]) -> str:
        trie = Trie()
        for w in words:
            trie.insert(w)
        n = len(s)
        pairs = []
        for i in range(n):
            node = trie
            for j in range(i, n):
                idx = ord(s[j])
                if node.children[idx] is None:
                    break
                node = node.children[idx]
                if node.is_end:
                    pairs.append([i, j])
        if not pairs:
            return s
        st, ed = pairs[0]
        t = []
        for a, b in pairs[1:]:
            if ed + 1 < a:
                t.append([st, ed])
                st, ed = a, b
            else:
                ed = max(ed, b)
        t.append([st, ed])

        ans = []
        i = j = 0
        while i < n:
            if j == len(t):
                ans.append(s[i:])
                break
            st, ed = t[j]
            if i < st:
                ans.append(s[i:st])
            ans.append('<b>')
            ans.append(s[st : ed + 1])
            ans.append('</b>')
            j += 1
            i = ed + 1

        return ''.join(ans)

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class Trie {
    Trie[] children = new Trie[128];
    boolean isEnd;

    public void insert(String word) {
        Trie node = this;
        for (char c : word.toCharArray()) {
            if (node.children[c] == null) {
                node.children[c] = new Trie();
            }
            node = node.children[c];
        }
        node.isEnd = true;
    }
}

class Solution {
    public String addBoldTag(String s, String[] words) {
        Trie trie = new Trie();
        for (String w : words) {
            trie.insert(w);
        }
        List<int[]> pairs = new ArrayList<>();
        int n = s.length();
        for (int i = 0; i < n; ++i) {
            Trie node = trie;
            for (int j = i; j < n; ++j) {
                int idx = s.charAt(j);
                if (node.children[idx] == null) {
                    break;
                }
                node = node.children[idx];
                if (node.isEnd) {
                    pairs.add(new int[] {i, j});
                }
            }
        }
        if (pairs.isEmpty()) {
            return s;
        }
        List<int[]> t = new ArrayList<>();
        int st = pairs.get(0)[0], ed = pairs.get(0)[1];
        for (int j = 1; j < pairs.size(); ++j) {
            int a = pairs.get(j)[0], b = pairs.get(j)[1];
            if (ed + 1 < a) {
                t.add(new int[] {st, ed});
                st = a;
                ed = b;
            } else {
                ed = Math.max(ed, b);
            }
        }
        t.add(new int[] {st, ed});
        int i = 0, j = 0;
        StringBuilder ans = new StringBuilder();
        while (i < n) {
            if (j == t.size()) {
                ans.append(s.substring(i));
                break;
            }
            st = t.get(j)[0];
            ed = t.get(j)[1];
            if (i < st) {
                ans.append(s.substring(i, st));
            }
            ++j;
            ans.append("<b>");
            ans.append(s.substring(st, ed + 1));
            ans.append("</b>");
            i = ed + 1;
        }
        return ans.toString();
    }
}

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class Trie {
public:
    vector<Trie*> children;
    bool isEnd;

    Trie() {
        children.resize(128);
        isEnd = false;
    }

    void insert(string word) {
        Trie* node = this;
        for (char c : word) {
            if (!node->children[c]) node->children[c] = new Trie();
            node = node->children[c];
        }
        node->isEnd = true;
    }
};

class Solution {
public:
    string addBoldTag(string s, vector<string>& words) {
        Trie* trie = new Trie();
        for (string w : words) trie->insert(w);
        int n = s.size();
        vector<pair<int, int>> pairs;
        for (int i = 0; i < n; ++i) {
            Trie* node = trie;
            for (int j = i; j < n; ++j) {
                int idx = s[j];
                if (!node->children[idx]) break;
                node = node->children[idx];
                if (node->isEnd) pairs.push_back({i, j});
            }
        }
        if (pairs.empty()) return s;
        vector<pair<int, int>> t;
        int st = pairs[0].first, ed = pairs[0].second;
        for (int i = 1; i < pairs.size(); ++i) {
            int a = pairs[i].first, b = pairs[i].second;
            if (ed + 1 < a) {
                t.push_back({st, ed});
                st = a, ed = b;
            } else
                ed = max(ed, b);
        }
        t.push_back({st, ed});
        string ans = "";
        int i = 0, j = 0;
        while (i < n) {
            if (j == t.size()) {
                ans += s.substr(i);
                break;
            }
            st = t[j].first, ed = t[j].second;
            if (i < st) ans += s.substr(i, st - i);
            ans += "<b>";
            ans += s.substr(st, ed - st + 1);
            ans += "</b>";
            i = ed + 1;
            ++j;
        }
        return ans;
    }
};

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type Trie struct {
    children [128]*Trie
    isEnd    bool
}

func newTrie() *Trie {
    return &Trie{}
}

func (this *Trie) insert(word string) {
    node := this
    for _, c := range word {
        if node.children[c] == nil {
            node.children[c] = newTrie()
        }
        node = node.children[c]
    }
    node.isEnd = true
}

func addBoldTag(s string, words []string) string {
    trie := newTrie()
    for _, w := range words {
        trie.insert(w)
    }
    n := len(s)
    var pairs [][]int
    for i := range s {
        node := trie
        for j := i; j < n; j++ {
            if node.children[s[j]] == nil {
                break
            }
            node = node.children[s[j]]
            if node.isEnd {
                pairs = append(pairs, []int{i, j})
            }
        }
    }
    if len(pairs) == 0 {
        return s
    }
    var t [][]int
    st, ed := pairs[0][0], pairs[0][1]
    for i := 1; i < len(pairs); i++ {
        a, b := pairs[i][0], pairs[i][1]
        if ed+1 < a {
            t = append(t, []int{st, ed})
            st, ed = a, b
        } else {
            ed = max(ed, b)
        }
    }
    t = append(t, []int{st, ed})
    var ans strings.Builder
    i, j := 0, 0
    for i < n {
        if j == len(t) {
            ans.WriteString(s[i:])
            break
        }
        st, ed = t[j][0], t[j][1]
        if i < st {
            ans.WriteString(s[i:st])
        }
        ans.WriteString("<b>")
        ans.WriteString(s[st : ed+1])
        ans.WriteString("</b>")
        i = ed + 1
        j++
    }
    return ans.String()
}

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