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2781. Length of the Longest Valid Substring

Description

You are given a string word and an array of strings forbidden.

A string is called valid if none of its substrings are present in forbidden.

Return the length of the longest valid substring of the string word.

A substring is a contiguous sequence of characters in a string, possibly empty.

 

Example 1:

Input: word = "cbaaaabc", forbidden = ["aaa","cb"]
Output: 4
Explanation: There are 11 valid substrings in word: "c", "b", "a", "ba", "aa", "bc", "baa", "aab", "ab", "abc" and "aabc". The length of the longest valid substring is 4. 
It can be shown that all other substrings contain either "aaa" or "cb" as a substring.

Example 2:

Input: word = "leetcode", forbidden = ["de","le","e"]
Output: 4
Explanation: There are 11 valid substrings in word: "l", "t", "c", "o", "d", "tc", "co", "od", "tco", "cod", and "tcod". The length of the longest valid substring is 4.
It can be shown that all other substrings contain either "de", "le", or "e" as a substring.

 

Constraints:

  • 1 <= word.length <= 105
  • word consists only of lowercase English letters.
  • 1 <= forbidden.length <= 105
  • 1 <= forbidden[i].length <= 10
  • forbidden[i] consists only of lowercase English letters.

Solutions

Solution 1

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class Solution:
    def longestValidSubstring(self, word: str, forbidden: List[str]) -> int:
        s = set(forbidden)
        ans = i = 0
        for j in range(len(word)):
            for k in range(j, max(j - 10, i - 1), -1):
                if word[k : j + 1] in s:
                    i = k + 1
                    break
            ans = max(ans, j - i + 1)
        return ans

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class Solution {
    public int longestValidSubstring(String word, List<String> forbidden) {
        var s = new HashSet<>(forbidden);
        int ans = 0, n = word.length();
        for (int i = 0, j = 0; j < n; ++j) {
            for (int k = j; k > Math.max(j - 10, i - 1); --k) {
                if (s.contains(word.substring(k, j + 1))) {
                    i = k + 1;
                    break;
                }
            }
            ans = Math.max(ans, j - i + 1);
        }
        return ans;
    }
}

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class Solution {
public:
    int longestValidSubstring(string word, vector<string>& forbidden) {
        unordered_set<string> s(forbidden.begin(), forbidden.end());
        int ans = 0, n = word.size();
        for (int i = 0, j = 0; j < n; ++j) {
            for (int k = j; k > max(j - 10, i - 1); --k) {
                if (s.count(word.substr(k, j - k + 1))) {
                    i = k + 1;
                    break;
                }
            }
            ans = max(ans, j - i + 1);
        }
        return ans;
    }
};

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func longestValidSubstring(word string, forbidden []string) (ans int) {
    s := map[string]bool{}
    for _, x := range forbidden {
        s[x] = true
    }
    n := len(word)
    for i, j := 0, 0; j < n; j++ {
        for k := j; k > max(j-10, i-1); k-- {
            if s[word[k:j+1]] {
                i = k + 1
                break
            }
        }
        ans = max(ans, j-i+1)
    }
    return
}

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function longestValidSubstring(word: string, forbidden: string[]): number {
    const s: Set<string> = new Set(forbidden);
    const n = word.length;
    let ans = 0;
    for (let i = 0, j = 0; j < n; ++j) {
        for (let k = j; k > Math.max(j - 10, i - 1); --k) {
            if (s.has(word.substring(k, j + 1))) {
                i = k + 1;
                break;
            }
        }
        ans = Math.max(ans, j - i + 1);
    }
    return ans;
}

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