2637. Promise Time Limit
Description
Given an asynchronous function fn
and a time t
in milliseconds, return a new time limited version of the input function. fn
takes arguments provided to the time limited function.
The time limited function should follow these rules:
- If the
fn
completes within the time limit oft
milliseconds, the time limited function should resolve with the result. - If the execution of the
fn
exceeds the time limit, the time limited function should reject with the string"Time Limit Exceeded"
.
Example 1:
Input: fn = async (n) => { await new Promise(res => setTimeout(res, 100)); return n * n; } inputs = [5] t = 50 Output: {"rejected":"Time Limit Exceeded","time":50} Explanation: const limited = timeLimit(fn, t) const start = performance.now() let result; try { const res = await limited(...inputs) result = {"resolved": res, "time": Math.floor(performance.now() - start)}; } catch (err) { result = {"rejected": err, "time": Math.floor(performance.now() - start)}; } console.log(result) // Output The provided function is set to resolve after 100ms. However, the time limit is set to 50ms. It rejects at t=50ms because the time limit was reached.
Example 2:
Input: fn = async (n) => { await new Promise(res => setTimeout(res, 100)); return n * n; } inputs = [5] t = 150 Output: {"resolved":25,"time":100} Explanation: The function resolved 5 * 5 = 25 at t=100ms. The time limit is never reached.
Example 3:
Input: fn = async (a, b) => { await new Promise(res => setTimeout(res, 120)); return a + b; } inputs = [5,10] t = 150 Output: {"resolved":15,"time":120} Explanation: ββββThe function resolved 5 + 10 = 15 at t=120ms. The time limit is never reached.
Example 4:
Input: fn = async () => { throw "Error"; } inputs = [] t = 1000 Output: {"rejected":"Error","time":0} Explanation: The function immediately throws an error.
Constraints:
0 <= inputs.length <= 10
0 <= t <= 1000
fn
returns a promise
Solutions
Solution 1
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