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2621. Sleep

Description

Given a positive integer millis, write an asynchronous function that sleeps for millis milliseconds. It can resolve any value.

 

Example 1:

Input: millis = 100
Output: 100
Explanation: It should return a promise that resolves after 100ms.
let t = Date.now();
sleep(100).then(() => {
  console.log(Date.now() - t); // 100
});

Example 2:

Input: millis = 200
Output: 200
Explanation: It should return a promise that resolves after 200ms.

 

Constraints:

  • 1 <= millis <= 1000

Solutions

Solution 1

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async function sleep(millis: number): Promise<void> {
    return new Promise(r => setTimeout(r, millis));
}

/**
 * let t = Date.now()
 * sleep(100).then(() => console.log(Date.now() - t)) // 100
 */
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/**
 * @param {number} millis
 * @return {Promise}
 */
async function sleep(millis) {
    return new Promise(r => setTimeout(r, millis));
}

/**
 * let t = Date.now()
 * sleep(100).then(() => console.log(Date.now() - t)) // 100
 */

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