Given two 0-indexed integer arrays nums1 and nums2, return a listanswerof size2where:
answer[0]is a list of all distinct integers innums1which are not present innums2.
answer[1]is a list of all distinct integers innums2which are not present innums1.
Note that the integers in the lists may be returned in any order.
Example 1:
Input: nums1 = [1,2,3], nums2 = [2,4,6]
Output: [[1,3],[4,6]]
Explanation:
For nums1, nums1[1] = 2 is present at index 0 of nums2, whereas nums1[0] = 1 and nums1[2] = 3 are not present in nums2. Therefore, answer[0] = [1,3].
For nums2, nums2[0] = 2 is present at index 1 of nums1, whereas nums2[1] = 4 and nums2[2] = 6 are not present in nums2. Therefore, answer[1] = [4,6].
Example 2:
Input: nums1 = [1,2,3,3], nums2 = [1,1,2,2]
Output: [[3],[]]
Explanation:
For nums1, nums1[2] and nums1[3] are not present in nums2. Since nums1[2] == nums1[3], their value is only included once and answer[0] = [3].
Every integer in nums2 is present in nums1. Therefore, answer[1] = [].
Constraints:
1 <= nums1.length, nums2.length <= 1000
-1000 <= nums1[i], nums2[i] <= 1000
Solutions
Solution 1: Hash Table
We define two hash tables $s1$ and $s2$ to store the elements in arrays $nums1$ and $nums2$ respectively. Then we traverse each element in $s1$. If this element is not in $s2$, we add it to the first list in the answer. Similarly, we traverse each element in $s2$. If this element is not in $s1$, we add it to the second list in the answer.
The time complexity is $O(n)$, and the space complexity is $O(n)$. Where $n$ is the length of the array.