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2169. Count Operations to Obtain Zero

Description

You are given two non-negative integers num1 and num2.

In one operation, if num1 >= num2, you must subtract num2 from num1, otherwise subtract num1 from num2.

  • For example, if num1 = 5 and num2 = 4, subtract num2 from num1, thus obtaining num1 = 1 and num2 = 4. However, if num1 = 4 and num2 = 5, after one operation, num1 = 4 and num2 = 1.

Return the number of operations required to make either num1 = 0 or num2 = 0.

 

Example 1:

Input: num1 = 2, num2 = 3
Output: 3
Explanation: 
- Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.
- Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1.
- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.
Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.
So the total number of operations required is 3.

Example 2:

Input: num1 = 10, num2 = 10
Output: 1
Explanation: 
- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0.
Now num1 = 0 and num2 = 10. Since num1 == 0, we are done.
So the total number of operations required is 1.

 

Constraints:

  • 0 <= num1, num2 <= 105

Solutions

Solution 1

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class Solution:
    def countOperations(self, num1: int, num2: int) -> int:
        ans = 0
        while num1 and num2:
            if num1 >= num2:
                num1, num2 = num2, num1
            num2 -= num1
            ans += 1
        return ans

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class Solution {
    public int countOperations(int num1, int num2) {
        int ans = 0;
        while (num1 != 0 && num2 != 0) {
            if (num1 >= num2) {
                num1 -= num2;
            } else {
                num2 -= num1;
            }
            ++ans;
        }
        return ans;
    }
}

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class Solution {
public:
    int countOperations(int num1, int num2) {
        int ans = 0;
        while (num1 && num2) {
            if (num1 > num2) swap(num1, num2);
            num2 -= num1;
            ++ans;
        }
        return ans;
    }
};

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func countOperations(num1 int, num2 int) int {
    ans := 0
    for num1 != 0 && num2 != 0 {
        if num1 > num2 {
            num1, num2 = num2, num1
        }
        num2 -= num1
        ans++
    }
    return ans
}

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function countOperations(num1: number, num2: number): number {
    let ans = 0;
    while (num1 && num2) {
        [num1, num2] = [Math.min(num1, num2), Math.abs(num1 - num2)];
        ans++;
    }
    return ans;
}

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