1945. Sum of Digits of String After Convert
Description
You are given a string s
consisting of lowercase English letters, and an integer k
. Your task is to convert the string into an integer by a special process, and then transform it by summing its digits repeatedly k
times. More specifically, perform the following steps:
- Convert
s
into an integer by replacing each letter with its position in the alphabet (i.e. replace'a'
with1
,'b'
with2
, ...,'z'
with26
). - Transform the integer by replacing it with the sum of its digits.
- Repeat the transform operation (step 2)
k
times in total.
For example, if s = "zbax"
and k = 2
, then the resulting integer would be 8
by the following operations:
- Convert:
"zbax" ➝ "(26)(2)(1)(24)" ➝ "262124" ➝ 262124
- Transform #1:
262124 ➝ 2 + 6 + 2 + 1 + 2 + 4 ➝ 17
- Transform #2:
17 ➝ 1 + 7 ➝ 8
Return the resulting integer after performing the operations described above.
Example 1:
Input: s = "iiii", k = 1
Output: 36
Explanation:
The operations are as follows:
- Convert: "iiii" ➝ "(9)(9)(9)(9)" ➝ "9999" ➝ 9999
- Transform #1: 9999 ➝ 9 + 9 + 9 + 9 ➝ 36
Thus the resulting integer is 36.
Example 2:
Input: s = "leetcode", k = 2
Output: 6
Explanation:
The operations are as follows:
- Convert: "leetcode" ➝ "(12)(5)(5)(20)(3)(15)(4)(5)" ➝ "12552031545" ➝ 12552031545
- Transform #1: 12552031545 ➝ 1 + 2 + 5 + 5 + 2 + 0 + 3 + 1 + 5 + 4 + 5 ➝ 33
- Transform #2: 33 ➝ 3 + 3 ➝ 6
Thus the resulting integer is 6.
Example 3:
Input: s = "zbax", k = 2
Output: 8
Constraints:
1 <= s.length <= 100
1 <= k <= 10
s
consists of lowercase English letters.
Solutions
Solution 1
1 2 3 4 5 6 7 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 |
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 |
|