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1777. Product's Price for Each Store πŸ”’

Description

Table: Products

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| product_id  | int     |
| store       | enum    |
| price       | int     |
+-------------+---------+
In SQL, (product_id, store) is the primary key for this table.
store is a category of type ('store1', 'store2', 'store3') where each represents the store this product is available at.
price is the price of the product at this store.

 

Find the price of each product in each store.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Products table:
+-------------+--------+-------+
| product_id  | store  | price |
+-------------+--------+-------+
| 0           | store1 | 95    |
| 0           | store3 | 105   |
| 0           | store2 | 100   |
| 1           | store1 | 70    |
| 1           | store3 | 80    |
+-------------+--------+-------+
Output: 
+-------------+--------+--------+--------+
| product_id  | store1 | store2 | store3 |
+-------------+--------+--------+--------+
| 0           | 95     | 100    | 105    |
| 1           | 70     | null   | 80     |
+-------------+--------+--------+--------+
Explanation: 
Product 0 price's are 95 for store1, 100 for store2 and, 105 for store3.
Product 1 price's are 70 for store1, 80 for store3 and, it's not sold in store2.

Solutions

Solution 1

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# Write your MySQL query statement below
SELECT
    product_id,
    SUM(IF(store = 'store1', price, NULL)) AS store1,
    SUM(IF(store = 'store2', price, NULL)) AS store2,
    SUM(IF(store = 'store3', price, NULL)) AS store3
FROM Products
GROUP BY 1;

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