Skip to content

177. Nth Highest Salary

Description

Table: Employee

+-------------+------+
| Column Name | Type |
+-------------+------+
| id          | int  |
| salary      | int  |
+-------------+------+
id is the primary key (column with unique values) for this table.
Each row of this table contains information about the salary of an employee.

 

Write a solution to find the nth highest salary from the Employee table. If there is no nth highest salary, return null.

The result format is in the following example.

 

Example 1:

Input: 
Employee table:
+----+--------+
| id | salary |
+----+--------+
| 1  | 100    |
| 2  | 200    |
| 3  | 300    |
+----+--------+
n = 2
Output: 
+------------------------+
| getNthHighestSalary(2) |
+------------------------+
| 200                    |
+------------------------+

Example 2:

Input: 
Employee table:
+----+--------+
| id | salary |
+----+--------+
| 1  | 100    |
+----+--------+
n = 2
Output: 
+------------------------+
| getNthHighestSalary(2) |
+------------------------+
| null                   |
+------------------------+

Solutions

Solution 1

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
import pandas as pd


def nth_highest_salary(employee: pd.DataFrame, N: int) -> pd.DataFrame:
    unique_salaries = employee.salary.unique()
    if len(unique_salaries) < N:
        return pd.DataFrame([np.NaN], columns=[f"getNthHighestSalary({N})"])
    else:
        salary = sorted(unique_salaries, reverse=True)[N - 1]
        return pd.DataFrame([salary], columns=[f"getNthHighestSalary({N})"])

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT
BEGIN
    SET N = N - 1;
  RETURN (
      # Write your MySQL query statement below.
      SELECT (
          SELECT DISTINCT salary
          FROM Employee
          ORDER BY salary DESC
          LIMIT 1 OFFSET N
      )
  );
END

Comments