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1614. Maximum Nesting Depth of the Parentheses

Description

Given a valid parentheses string s, return the nesting depth of s. The nesting depth is the maximum number of nested parentheses.

 

Example 1:

Input: s = "(1+(2*3)+((8)/4))+1"

Output: 3

Explanation:

Digit 8 is inside of 3 nested parentheses in the string.

Example 2:

Input: s = "(1)+((2))+(((3)))"

Output: 3

Explanation:

Digit 3 is inside of 3 nested parentheses in the string.

Example 3:

Input: s = "()(())((()()))"

Output: 3

 

Constraints:

  • 1 <= s.length <= 100
  • s consists of digits 0-9 and characters '+', '-', '*', '/', '(', and ')'.
  • It is guaranteed that parentheses expression s is a VPS.

Solutions

Solution 1: Traversal

We use a variable \(d\) to record the current depth, initially \(d = 0\).

Traverse the string \(s\). When encountering a left parenthesis, increment the depth \(d\) by one and update the answer to be the maximum of the current depth \(d\) and the answer. When encountering a right parenthesis, decrement the depth \(d\) by one.

Finally, return the answer.

The time complexity is \(O(n)\), where \(n\) is the length of the string \(s\). The space complexity is \(O(1)\).

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class Solution:
    def maxDepth(self, s: str) -> int:
        ans = d = 0
        for c in s:
            if c == '(':
                d += 1
                ans = max(ans, d)
            elif c == ')':
                d -= 1
        return ans

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class Solution {
    public int maxDepth(String s) {
        int ans = 0, d = 0;
        for (int i = 0; i < s.length(); ++i) {
            char c = s.charAt(i);
            if (c == '(') {
                ans = Math.max(ans, ++d);
            } else if (c == ')') {
                --d;
            }
        }
        return ans;
    }
}

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class Solution {
public:
    int maxDepth(string s) {
        int ans = 0, d = 0;
        for (char& c : s) {
            if (c == '(') {
                ans = max(ans, ++d);
            } else if (c == ')') {
                --d;
            }
        }
        return ans;
    }
};

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func maxDepth(s string) (ans int) {
    d := 0
    for _, c := range s {
        if c == '(' {
            d++
            ans = max(ans, d)
        } else if c == ')' {
            d--
        }
    }
    return
}

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function maxDepth(s: string): number {
    let ans = 0;
    let d = 0;
    for (const c of s) {
        if (c === '(') {
            ans = Math.max(ans, ++d);
        } else if (c === ')') {
            --d;
        }
    }
    return ans;
}

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/**
 * @param {string} s
 * @return {number}
 */
var maxDepth = function (s) {
    let ans = 0;
    let d = 0;
    for (const c of s) {
        if (c === '(') {
            ans = Math.max(ans, ++d);
        } else if (c === ')') {
            --d;
        }
    }
    return ans;
};

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public class Solution {
    public int MaxDepth(string s) {
        int ans = 0, d = 0;
        foreach(char c in s) {
            if (c == '(') {
                ans = Math.Max(ans, ++d);
            } else if (c == ')') {
                --d;
            }
        }
        return ans;
    }
}

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