1369. Get the Second Most Recent Activity 🔒

Description

Table: UserActivity

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| username      | varchar |
| activity      | varchar |
| startDate     | Date    |
| endDate       | Date    |
+---------------+---------+
This table may contain duplicates rows.
This table contains information about the activity performed by each user in a period of time.
A person with username performed an activity from startDate to endDate.

 

Write a solution to show the second most recent activity of each user.

If the user only has one activity, return that one. A user cannot perform more than one activity at the same time.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
UserActivity table:
+------------+--------------+-------------+-------------+
| username   | activity     | startDate   | endDate     |
+------------+--------------+-------------+-------------+
| Alice      | Travel       | 2020-02-12  | 2020-02-20  |
| Alice      | Dancing      | 2020-02-21  | 2020-02-23  |
| Alice      | Travel       | 2020-02-24  | 2020-02-28  |
| Bob        | Travel       | 2020-02-11  | 2020-02-18  |
+------------+--------------+-------------+-------------+
Output: 
+------------+--------------+-------------+-------------+
| username   | activity     | startDate   | endDate     |
+------------+--------------+-------------+-------------+
| Alice      | Dancing      | 2020-02-21  | 2020-02-23  |
| Bob        | Travel       | 2020-02-11  | 2020-02-18  |
+------------+--------------+-------------+-------------+
Explanation: 
The most recent activity of Alice is Travel from 2020-02-24 to 2020-02-28, before that she was dancing from 2020-02-21 to 2020-02-23.
Bob only has one record, we just take that one.

Solutions

Solution 1

MySQL

SELECT
    username,
    activity,
    startdate,
    enddate
FROM
    (
        SELECT
            *,
            RANK() OVER (
                PARTITION BY username
                ORDER BY startdate DESC
            ) AS rk,
            COUNT(username) OVER (PARTITION BY username) AS cnt
        FROM UserActivity
    ) AS a
WHERE a.rk = 2 OR a.cnt = 1;

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