Each node in the graph contains a value (int) and a list (List[Node]) of its neighbors.
class Node {
public int val;
public List<Node> neighbors;
}
Test case format:
For simplicity, each node's value is the same as the node's index (1-indexed). For example, the first node with val == 1, the second node with val == 2, and so on. The graph is represented in the test case using an adjacency list.
An adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.
The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.
Example 1:
Input: adjList = [[2,4],[1,3],[2,4],[1,3]]
Output: [[2,4],[1,3],[2,4],[1,3]]
Explanation: There are 4 nodes in the graph.
1st node (val = 1)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
2nd node (val = 2)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
3rd node (val = 3)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
4th node (val = 4)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
Example 2:
Input: adjList = [[]]
Output: [[]]
Explanation: Note that the input contains one empty list. The graph consists of only one node with val = 1 and it does not have any neighbors.
Example 3:
Input: adjList = []
Output: []
Explanation: This an empty graph, it does not have any nodes.
Constraints:
The number of nodes in the graph is in the range [0, 100].
1 <= Node.val <= 100
Node.val is unique for each node.
There are no repeated edges and no self-loops in the graph.
The Graph is connected and all nodes can be visited starting from the given node.
Solutions
Solution 1
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"""# Definition for a Node.class Node: def __init__(self, val = 0, neighbors = None): self.val = val self.neighbors = neighbors if neighbors is not None else []"""classSolution:defcloneGraph(self,node:'Node')->'Node':visited=defaultdict()defclone(node):ifnodeisNone:returnNoneifnodeinvisited:returnvisited[node]c=Node(node.val)visited[node]=cforeinnode.neighbors:c.neighbors.append(clone(e))returncreturnclone(node)
/*// Definition for a Node.class Node { public int val; public List<Node> neighbors; public Node() { val = 0; neighbors = new ArrayList<Node>(); } public Node(int _val) { val = _val; neighbors = new ArrayList<Node>(); } public Node(int _val, ArrayList<Node> _neighbors) { val = _val; neighbors = _neighbors; }}*/classSolution{privateMap<Node,Node>visited=newHashMap<>();publicNodecloneGraph(Nodenode){if(node==null){returnnull;}if(visited.containsKey(node)){returnvisited.get(node);}Nodeclone=newNode(node.val);visited.put(node,clone);for(Nodee:node.neighbors){clone.neighbors.add(cloneGraph(e));}returnclone;}}
/** * Definition for a Node. * type Node struct { * Val int * Neighbors []*Node * } */funccloneGraph(node*Node)*Node{visited:=map[*Node]*Node{}varclonefunc(node*Node)*Nodeclone=func(node*Node)*Node{ifnode==nil{returnnil}if_,ok:=visited[node];ok{returnvisited[node]}c:=&Node{node.Val,[]*Node{}}visited[node]=cfor_,e:=rangenode.Neighbors{c.Neighbors=append(c.Neighbors,clone(e))}returnc}returnclone(node)}