1285. Find the Start and End Number of Continuous Ranges 🔒

Description

Table: Logs

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| log_id        | int     |
+---------------+---------+
log_id is the column of unique values for this table.
Each row of this table contains the ID in a log Table.

 

Write a solution to find the start and end number of continuous ranges in the table Logs.

Return the result table ordered by start_id.

The result format is in the following example.

 

Example 1:

Input: 
Logs table:
+------------+
| log_id     |
+------------+
| 1          |
| 2          |
| 3          |
| 7          |
| 8          |
| 10         |
+------------+
Output: 
+------------+--------------+
| start_id   | end_id       |
+------------+--------------+
| 1          | 3            |
| 7          | 8            |
| 10         | 10           |
+------------+--------------+
Explanation: 
The result table should contain all ranges in table Logs.
From 1 to 3 is contained in the table.
From 4 to 6 is missing in the table
From 7 to 8 is contained in the table.
Number 9 is missing from the table.
Number 10 is contained in the table.

Solutions

Solution 1: Group By + Window Function

We need to find a way to group a continuous sequence of logs into the same group, and then aggregate each group to obtain the start and end logs of each group.

There are two ways to implement grouping:

1. By calculating the difference between each log and the previous log, if the difference is $1$, then the two logs are continuous, and we set $delta$ to $0$, otherwise we set it to $1$. Then we take the prefix sum of $delta$ to obtain the grouping identifier for each row.
2. By calculating the difference between the current log and its row number, we obtain the grouping identifier for each row.

MySQL

# Write your MySQL query statement below
WITH
    T AS (
        SELECT
            log_id,
            SUM(delta) OVER (ORDER BY log_id) AS pid
        FROM
            (
                SELECT
                    log_id,
                    IF((log_id - LAG(log_id) OVER (ORDER BY log_id)) = 1, 0, 1) AS delta
                FROM Logs
            ) AS t
    )
SELECT MIN(log_id) AS start_id, MAX(log_id) AS end_id
FROM T
GROUP BY pid;

Solution 2

MySQL

# Write your MySQL query statement below
WITH
    T AS (
        SELECT
            log_id,
            log_id - ROW_NUMBER() OVER (ORDER BY log_id) AS pid
        FROM Logs
    )
SELECT MIN(log_id) AS start_id, MAX(log_id) AS end_id
FROM T
GROUP BY pid;

Comments