Description
Given a matrix and a target, return the number of non-empty submatrices that sum to target.
A submatrix x1, y1, x2, y2 is the set of all cells matrix[x][y] with x1 <= x <= x2 and y1 <= y <= y2.
Two submatrices (x1, y1, x2, y2) and (x1', y1', x2', y2') are different if they have some coordinate that is different: for example, if x1 != x1'.
Example 1:
Input: matrix = [[0,1,0],[1,1,1],[0,1,0]], target = 0
Output: 4
Explanation: The four 1x1 submatrices that only contain 0.
Example 2:
Input: matrix = [[1,-1],[-1,1]], target = 0
Output: 5
Explanation: The two 1x2 submatrices, plus the two 2x1 submatrices, plus the 2x2 submatrix.
Example 3:
Input: matrix = [[904]], target = 0
Output: 0
Constraints:
1 <= matrix.length <= 1001 <= matrix[0].length <= 100-1000 <= matrix[i][j] <= 1000-10^8 <= target <= 10^8
Solutions
Solution 1
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21 | class Solution:
def numSubmatrixSumTarget(self, matrix: List[List[int]], target: int) -> int:
def f(nums: List[int]) -> int:
d = defaultdict(int)
d[0] = 1
cnt = s = 0
for x in nums:
s += x
cnt += d[s - target]
d[s] += 1
return cnt
m, n = len(matrix), len(matrix[0])
ans = 0
for i in range(m):
col = [0] * n
for j in range(i, m):
for k in range(n):
col[k] += matrix[j][k]
ans += f(col)
return ans
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28 | class Solution {
public int numSubmatrixSumTarget(int[][] matrix, int target) {
int m = matrix.length, n = matrix[0].length;
int ans = 0;
for (int i = 0; i < m; ++i) {
int[] col = new int[n];
for (int j = i; j < m; ++j) {
for (int k = 0; k < n; ++k) {
col[k] += matrix[j][k];
}
ans += f(col, target);
}
}
return ans;
}
private int f(int[] nums, int target) {
Map<Integer, Integer> d = new HashMap<>();
d.put(0, 1);
int s = 0, cnt = 0;
for (int x : nums) {
s += x;
cnt += d.getOrDefault(s - target, 0);
d.merge(s, 1, Integer::sum);
}
return cnt;
}
}
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30 | class Solution {
public:
int numSubmatrixSumTarget(vector<vector<int>>& matrix, int target) {
int m = matrix.size(), n = matrix[0].size();
int ans = 0;
for (int i = 0; i < m; ++i) {
vector<int> col(n);
for (int j = i; j < m; ++j) {
for (int k = 0; k < n; ++k) {
col[k] += matrix[j][k];
}
ans += f(col, target);
}
}
return ans;
}
int f(vector<int>& nums, int target) {
unordered_map<int, int> d{{0, 1}};
int cnt = 0, s = 0;
for (int& x : nums) {
s += x;
if (d.count(s - target)) {
cnt += d[s - target];
}
++d[s];
}
return cnt;
}
};
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26 | func numSubmatrixSumTarget(matrix [][]int, target int) (ans int) {
m, n := len(matrix), len(matrix[0])
for i := 0; i < m; i++ {
col := make([]int, n)
for j := i; j < m; j++ {
for k := 0; k < n; k++ {
col[k] += matrix[j][k]
}
ans += f(col, target)
}
}
return
}
func f(nums []int, target int) (cnt int) {
d := map[int]int{0: 1}
s := 0
for _, x := range nums {
s += x
if v, ok := d[s-target]; ok {
cnt += v
}
d[s]++
}
return
}
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30 | function numSubmatrixSumTarget(matrix: number[][], target: number): number {
const m = matrix.length;
const n = matrix[0].length;
let ans = 0;
for (let i = 0; i < m; ++i) {
const col: number[] = new Array(n).fill(0);
for (let j = i; j < m; ++j) {
for (let k = 0; k < n; ++k) {
col[k] += matrix[j][k];
}
ans += f(col, target);
}
}
return ans;
}
function f(nums: number[], target: number): number {
const d: Map<number, number> = new Map();
d.set(0, 1);
let cnt = 0;
let s = 0;
for (const x of nums) {
s += x;
if (d.has(s - target)) {
cnt += d.get(s - target)!;
}
d.set(s, (d.get(s) || 0) + 1);
}
return cnt;
}
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