题目描述
给定一个可能有重复数字的整数数组 candidates
和一个目标数 target
,找出 candidates
中所有可以使数字和为 target
的组合。
candidates
中的每个数字在每个组合中只能使用一次,解集不能包含重复的组合。
示例 1:
输入: candidates = [10,1,2,7,6,1,5], target = 8,
输出:
[
[1,1,6],
[1,2,5],
[1,7],
[2,6]
]
示例 2:
输入: candidates = [2,5,2,1,2], target = 5,
输出:
[
[1,2,2],
[5]
]
提示:
1 <= candidates.length <= 100
1 <= candidates[i] <= 50
1 <= target <= 30
注意:本题与主站 40 题相同: https://leetcode.cn/problems/combination-sum-ii/
解法
方法一
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19 | class Solution:
def combinationSum2(self, candidates: List[int], target: int) -> List[List[int]]:
def dfs(u, s, t):
if s > target:
return
if s == target:
ans.append(t[:])
return
for i in range(u, len(candidates)):
if i > u and candidates[i] == candidates[i - 1]:
continue
t.append(candidates[i])
dfs(i + 1, s + candidates[i], t)
t.pop()
ans = []
candidates.sort()
dfs(0, 0, [])
return ans
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32 | class Solution {
private List<List<Integer>> ans;
private int[] candidates;
private int target;
public List<List<Integer>> combinationSum2(int[] candidates, int target) {
ans = new ArrayList<>();
Arrays.sort(candidates);
this.target = target;
this.candidates = candidates;
dfs(0, 0, new ArrayList<>());
return ans;
}
private void dfs(int u, int s, List<Integer> t) {
if (s > target) {
return;
}
if (s == target) {
ans.add(new ArrayList<>(t));
return;
}
for (int i = u; i < candidates.length; ++i) {
if (i > u && candidates[i] == candidates[i - 1]) {
continue;
}
t.add(candidates[i]);
dfs(i + 1, s + candidates[i], t);
t.remove(t.size() - 1);
}
}
}
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30 | class Solution {
public:
vector<int> candidates;
vector<vector<int>> ans;
vector<int> t;
int target;
vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
sort(candidates.begin(), candidates.end());
this->candidates = candidates;
this->target = target;
vector<int> t;
dfs(0, 0, t);
return ans;
}
void dfs(int u, int s, vector<int>& t) {
if (s > target) return;
if (s == target) {
ans.push_back(t);
return;
}
for (int i = u; i < candidates.size(); ++i) {
if (i > u && candidates[i] == candidates[i - 1]) continue;
t.push_back(candidates[i]);
dfs(i + 1, s + candidates[i], t);
t.pop_back();
}
}
};
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26 | func combinationSum2(candidates []int, target int) [][]int {
var ans [][]int
var t []int
sort.Ints(candidates)
var dfs func(u, s int, t []int)
dfs = func(u, s int, t []int) {
if s > target {
return
}
if s == target {
ans = append(ans, slices.Clone(t))
return
}
for i := u; i < len(candidates); i++ {
if i > u && candidates[i] == candidates[i-1] {
continue
}
t = append(t, candidates[i])
dfs(i+1, s+candidates[i], t)
t = t[:len(t)-1]
}
}
dfs(0, 0, t)
return ans
}
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71 | using System;
using System.Collections.Generic;
using System.Linq;
public class Solution
{
public IList<IList<int>> CombinationSum2(int[] candidates, int target)
{
var dict = new SortedDictionary<int, int>(candidates.GroupBy(c => c).ToDictionary(g => g.Key, g => g.Count()));
var paths = new List<Tuple<int, int>>[target + 1];
paths[0] = new List<Tuple<int, int>>();
foreach (var pair in dict)
{
for (var j = target; j >= 0; --j)
{
for (var k = 1; k <= pair.Value && j - pair.Key * k >= 0; ++k)
{
if (paths[j - pair.Key * k] != null)
{
if (paths[j] == null)
{
paths[j] = new List<Tuple<int, int>>();
}
paths[j].Add(Tuple.Create(pair.Key, k));
}
}
}
}
var results = new List<IList<int>>();
if (paths[target] != null) GenerateResults(results, new Stack<int>(), paths, target, paths[target].Count - 1);
return results;
}
private void GenerateResults(IList<IList<int>> results, Stack<int> result, List<Tuple<int, int>>[] paths, int remaining,
int maxIndex)
{
if (remaining == 0)
{
results.Add(new List<int>(result));
return;
}
for (var i = maxIndex; i >= 0; --i)
{
var path = paths[remaining][i];
for (var j = 0; j < path.Item2; ++j)
{
result.Push(path.Item1);
}
var nextMaxIndex = paths[remaining - path.Item1 * path.Item2].BinarySearch(Tuple.Create(path.Item1, int.MinValue), Comparer.Instance);
nextMaxIndex = ~nextMaxIndex - 1;
GenerateResults(results, result, paths, remaining - path.Item1 * path.Item2, nextMaxIndex);
for (var j = 0; j < path.Item2; ++j)
{
result.Pop();
}
}
}
}
class Comparer : IComparer<Tuple<int, int>>
{
public int Compare(Tuple<int, int> x, Tuple<int, int> y)
{
if (x.Item1 < y.Item1) return -1;
if (x.Item1 > y.Item1) return 1;
return x.Item2.CompareTo(y.Item2);
}
public static Comparer Instance = new Comparer();
}
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29 | class Solution {
private var ans: [[Int]] = []
private var candidates: [Int] = []
private var target: Int = 0
func combinationSum2(_ candidates: [Int], _ target: Int) -> [[Int]] {
self.ans = []
self.target = target
self.candidates = candidates.sorted()
dfs(0, 0, [])
return ans
}
private func dfs(_ index: Int, _ sum: Int, _ current: [Int]) {
if sum > target {
return
}
if sum == target {
ans.append(current)
return
}
for i in index..<candidates.count {
if i > index && candidates[i] == candidates[i - 1] {
continue
}
dfs(i + 1, sum + candidates[i], current + [candidates[i]])
}
}
}
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