535. TinyURL 的加密与解密

题目描述

TinyURL 是一种 URL 简化服务，比如：当你输入一个 URL https://leetcode.com/problems/design-tinyurl 时，它将返回一个简化的URL http://tinyurl.com/4e9iAk 。请你设计一个类来加密与解密 TinyURL 。

加密和解密算法如何设计和运作是没有限制的，你只需要保证一个 URL 可以被加密成一个 TinyURL ，并且这个 TinyURL 可以用解密方法恢复成原本的 URL 。

实现 Solution 类：

Solution() 初始化 TinyURL 系统对象。
String encode(String longUrl) 返回 longUrl 对应的 TinyURL 。
String decode(String shortUrl) 返回 shortUrl 原本的 URL 。题目数据保证给定的 shortUrl 是由同一个系统对象加密的。

示例：

输入：url = "https://leetcode.com/problems/design-tinyurl"
输出："https://leetcode.com/problems/design-tinyurl"

解释：
Solution obj = new Solution();
string tiny = obj.encode(url); // 返回加密后得到的 TinyURL 。
string ans = obj.decode(tiny); // 返回解密后得到的原本的 URL 。

提示：

1 <= url.length <= 10⁴
题目数据保证 url 是一个有效的 URL

解法

方法一：哈希表

Python3JavaC++Go

class Codec:
    def __init__(self):
        self.m = defaultdict()
        self.idx = 0
        self.domain = 'https://tinyurl.com/'

    def encode(self, longUrl: str) -> str:
        """Encodes a URL to a shortened URL."""
        self.idx += 1
        self.m[str(self.idx)] = longUrl
        return f'{self.domain}{self.idx}'

    def decode(self, shortUrl: str) -> str:
        """Decodes a shortened URL to its original URL."""
        idx = shortUrl.split('/')[-1]
        return self.m[idx]


# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.decode(codec.encode(url))

public class Codec {
    private Map<String, String> m = new HashMap<>();
    private int idx = 0;
    private String domain = "https://tinyurl.com/";

    // Encodes a URL to a shortened URL.
    public String encode(String longUrl) {
        String v = String.valueOf(++idx);
        m.put(v, longUrl);
        return domain + v;
    }

    // Decodes a shortened URL to its original URL.
    public String decode(String shortUrl) {
        int i = shortUrl.lastIndexOf('/') + 1;
        return m.get(shortUrl.substring(i));
    }
}

// Your Codec object will be instantiated and called as such:
// Codec codec = new Codec();
// codec.decode(codec.encode(url));

class Solution {
public:
    // Encodes a URL to a shortened URL.
    string encode(string longUrl) {
        string v = to_string(++idx);
        m[v] = longUrl;
        return domain + v;
    }

    // Decodes a shortened URL to its original URL.
    string decode(string shortUrl) {
        int i = shortUrl.rfind('/') + 1;
        return m[shortUrl.substr(i, shortUrl.size() - i)];
    }

private:
    unordered_map<string, string> m;
    int idx = 0;
    string domain = "https://tinyurl.com/";
};

// Your Solution object will be instantiated and called as such:
// Solution solution;
// solution.decode(solution.encode(url));

type Codec struct {
    m   map[int]string
    idx int
}

func Constructor() Codec {
    m := map[int]string{}
    return Codec{m, 0}
}

// Encodes a URL to a shortened URL.
func (this *Codec) encode(longUrl string) string {
    this.idx++
    this.m[this.idx] = longUrl
    return "https://tinyurl.com/" + strconv.Itoa(this.idx)
}

// Decodes a shortened URL to its original URL.
func (this *Codec) decode(shortUrl string) string {
    i := strings.LastIndexByte(shortUrl, '/')
    v, _ := strconv.Atoi(shortUrl[i+1:])
    return this.m[v]
}

/**
 * Your Codec object will be instantiated and called as such:
 * obj := Constructor();
 * url := obj.encode(longUrl);
 * ans := obj.decode(url);
 */

535. TinyURL 的加密与解密

题目描述

解法

方法一：哈希表

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